///

/// info | Інформація

Ви також можете використовувати:

* `response_model_exclude_defaults=True`
* `response_model_exclude_none=True`

If you've found a security problem, please follow our [bug bounty][security] program.

If you've found a bug, please contribute a failing test case so we can study and fix it.

If you have a new feature idea, please build it in an external library. There are
[many libraries][works_with_okhttp] that sit on top or hook in via existing APIs. If you build
something that integrates with OkHttp, tell us so that we can link it!

If you've found a security problem, please follow our [bug bounty][security] program.

If you've found a bug, please contribute a failing test case so we can study and fix it.

If you have a new feature idea, please build it in an external library. There are
[many libraries][works_with_okhttp] that sit on top or hook in via existing APIs. If you build
something that integrates with OkHttp, tell us so that we can link it!

### 당신만의 비동기 코드 작성하기

Starlette(그리고 FastAPI)는 <a href="https://anyio.readthedocs.io/en/stable/" class="external-link" target="_blank">AnyIO</a>를 기반으로 하고있고, 따라서 파이썬 표준 라이브러리인 <a href="https://docs.python.org/3/library/asyncio-task.html" class="external-link" target="_blank">asyncio</a> 및 <a href="https://trio.readthedocs.io/en/stable/" class="external-link" target="_blank">Trio</a>와 호환됩니다.

Ahora, veamos cómo podrías usar eso para devolver un response personalizado.

Digamos que quieres devolver un response en <a href="https://en.wikipedia.org/wiki/XML" class="external-link" target="_blank">XML</a>.

Podrías poner tu contenido XML en un string, poner eso en un `Response`, y devolverlo:

{* ../../docs_src/response_directly/tutorial002.py hl[1,18] *}

## Notas

Sehen wir uns nun an, wie Sie damit eine benutzerdefinierte Response zurückgeben können.

Nehmen wir an, Sie möchten eine <a href="https://en.wikipedia.org/wiki/XML" class="external-link" target="_blank">XML</a>-Response zurückgeben.

Sie könnten Ihren XML-Inhalt als String in eine `Response` einfügen und sie zurückgeben:

{* ../../docs_src/response_directly/tutorial002.py hl[1,18] *}

//
// Usage:
//
//	go run ../../mkzip.go ../../zoneinfo.zip
//
// We use this program instead of 'zip -0 -r ../../zoneinfo.zip *' to get
// a reproducible generator that does not depend on which version of the
// external zip tool is used or the ordering of file names in a directory
// or the current time.
package main

import (
	"archive/zip"
	"bytes"
	"flag"
	"fmt"
	"hash/crc32"
	"io/fs"
	"log"
	"os"

**FastAPI** використовує його для того, якщо Ви використовуєте модель Pydantic у `response_model` і у ваших даних є помилка, Ви побачили помилку у своєму журналі.

Але клієнт/користувач не побачить її. Натомість клієнт отримає "Internal Server Error" зі статусом HTTP `500`.

Sie können im Docstring <a href="https://en.wikipedia.org/wiki/Markdown" class="external-link" target="_blank">Markdown</a> schreiben, es wird korrekt interpretiert und angezeigt (die Einrückung des Docstring beachtend).

{* ../../docs_src/path_operation_configuration/tutorial004_py310.py hl[17:25] *}

Unabhängige TechEmpower-Benchmarks zeigen, **FastAPI**-Anwendungen, die unter Uvicorn ausgeführt werden, gehören zu <a href="https://www.techempower.com/benchmarks/#section=test&runid=7464e520-0dc2-473d-bd34-dbdfd7e85911&hw=ph&test=query&l=zijzen-7" class="external-link" target="_blank">den schnellsten existierenden Python-Frameworks</a>, nur Starlette und Uvicorn selbst (intern von FastAPI verwendet) sind schneller.