protected <E extends Comparable<? super E>> SortedSet<E> copyOf(E[] elements) {
    return ImmutableSortedSet.copyOf(elements);
  }

  @Override
  protected <E extends Comparable<? super E>> SortedSet<E> copyOf(
      Collection<? extends E> elements) {
    return ImmutableSortedSet.copyOf(elements);
  }

  @Override
  protected <E extends Comparable<? super E>> SortedSet<E> copyOf(Iterable<? extends E> elements) {

  private final BaseGraph<N> backingGraph;

  ImmutableGraph(BaseGraph<N> backingGraph) {
    this.backingGraph = backingGraph;
  }

  /** Returns an immutable copy of {@code graph}. */
  public static <N> ImmutableGraph<N> copyOf(Graph<N> graph) {
    return (graph instanceof ImmutableGraph)
        ? (ImmutableGraph<N>) graph
        : new ImmutableGraph<N>(
            new StandardValueGraph<N, Presence>(

    Collection<String> copy = SerializableTester.reserializeAndAssert(c);
    assertThat(copy).containsExactly("a", "a", "b").inOrder();
  }

  @J2ktIncompatible
  @GwtIncompatible // SerializableTester
  public void testSerialization_elementSet() {
    Multiset<String> c = ImmutableMultiset.of("a", "b", "a");

    Graph<Integer> copy = copyOf(undirectedGraph);
    assertThat(copy).isEqualTo(undirectedGraph);
  }

  @Test
  public void copyOf_directedValueGraph() {
    ValueGraph<Integer, String> directedGraph = buildDirectedValueGraph();

    ValueGraph<Integer, String> copy = copyOf(directedGraph);
    assertThat(copy).isEqualTo(directedGraph);
  }

  @Test

   *
   * <p><b>Performance note:</b> This method will sometimes recognize that the actual copy operation
   * is unnecessary; for example, {@code copyOf(copyOf(anArrayList))} will copy the data only once.
   * This reduces the expense of habitually making defensive copies at API boundaries. However, the
   * precise conditions for skipping the copy operation are undefined.
   *
   * @throws NullPointerException if any of {@code elements} is null

      }
    },
    COPY_OF_ARRAY {
      @Override
      public ImmutableSet<Object> create(List<?> list) {
        return ImmutableSet.copyOf(list.toArray());
      }
    },
    COPY_OF_LIST {
      @Override
      public ImmutableSet<Object> create(List<?> list) {
        return ImmutableSet.copyOf(list);
      }
    },
    BUILDER_ADD_ONE_BY_ONE {
      @Override

    ImmutableBiMap<String, Integer> copy =
        ImmutableBiMap.copyOf(Collections.<String, Integer>emptyMap());
    assertEquals(Collections.<String, Integer>emptyMap(), copy);
    assertSame(copy, ImmutableBiMap.copyOf(copy));
    assertSame(ImmutableBiMap.of(), copy);
  }

  public void testCopyOfSingletonMap() {
    ImmutableBiMap<String, Integer> copy =

   */
  public static <E> ImmutableSortedSet<E> copyOf(
      Comparator<? super E> comparator, Collection<? extends E> elements) {
    return copyOf(comparator, (Iterable<? extends E>) elements);
  }

  /**
   * Returns an immutable sorted set containing the elements of a sorted set, sorted by the same
   * {@code Comparator}. That behavior differs from {@link #copyOf(Iterable)}, which always uses the

    inputOrder.arrange(list);
    input = ImmutableList.copyOf(list);
  }

  @Benchmark
  int collections(int reps) {
    int dummy = 0;
    // Yes, this could be done more elegantly
    if (mutable) {
      for (int i = 0; i < reps; i++) {
        List<Integer> copy = new ArrayList<>(input);
        Collections.sort(copy);
        dummy += copy.get(0);
      }
    } else {
      for (int i = 0; i < reps; i++) {

  protected <E extends Comparable<? super E>> SortedSet<E> copyOf(E[] elements) {
    return ImmutableSortedSet.copyOf(elements);
  }

  @Override
  protected <E extends Comparable<? super E>> SortedSet<E> copyOf(
      Collection<? extends E> elements) {
    return ImmutableSortedSet.copyOf(elements);
  }

  @Override
  protected <E extends Comparable<? super E>> SortedSet<E> copyOf(Iterable<? extends E> elements) {