continue;
            }

            char ch = s.charAt(pos);
            pos++;
            if (ch == '\\') {
                sb.append(ch);
                if (pos >= end) {
                    break; // ERROR, or let it go?
                }
                ch = s.charAt(pos);
                pos++;
            }

            sb.append(ch);
        }

O **FastAPI** pegará este modelo, gerará o esquema JSON dele e incluirá no local correto do OpenAPI.

Por exemplo, para declarar um outro retorno com o status code `404` e um modelo do Pydantic chamado `Message`, você pode escrever:

{* ../../docs_src/additional_responses/tutorial001.py hl[18,22] *}

/// note | Nota

Lembre-se que você deve retornar o `JSONResponse` diretamente.

///

  }

  static void checkExactMatches(CharMatcher m, char[] chars) {
    Set<Character> positive = Sets.newHashSetWithExpectedSize(chars.length);
    for (char c : chars) {
      positive.add(c);
    }
    for (int c = 0; c <= Character.MAX_VALUE; c++) {
      assertFalse(positive.contains(Character.valueOf((char) c)) ^ m.matches((char) c));
    }
  }

  static char[] randomChars(Random rand, int size) {

labels.user_homePostalAddress=Adresse postale personnelle
labels.homePostalAddress=Adresse postale personnelle
labels.user_labeledURI=labeledURI
labels.labeledURI=labeledURI
labels.user_roomNumber=Numéro de chambre
labels.roomNumber=Numéro de chambre
labels.user_description=Description
labels.description=Description
labels.user_title=Titre
labels.title=Titre
labels.user_pager=Téléavertisseur
labels.pager=Téléavertisseur

  }

  /** Helper to manually escape a 7-bit ascii character */
  private String escapeAscii(char c) {
    Preconditions.checkArgument(c < 128);
    String hex = "0123456789ABCDEF";
    return "%" + hex.charAt((c >> 4) & 0xf) + hex.charAt(c & 0xf);
  }

d},errorMessage:"",errorMessageKey:"badStrength",calculatePasswordStrength:function(a){if(a.length<4)return 0;var b=0,c=function(a,b){for(var c="",d=0;d<b.length;d++){for(var e=!0,f=0;f<a&&f+d+a<b.length;f++)e=e&&b.charAt(f+d)===b.charAt(f+d+a);f<a&&(e=!1),e?(d+=a-1,e=!1):c+=b.charAt(d)}return c};return b+=4*a.length,b+=1*(c(1,a).length-a.length),b+=1*(c(2,a).length-a.length),b+=1*(c(3,a).length-a.length),b+=1*(c(4,a).length-a.length),a.match(/(.*[0-9].*[0-9].*[0-9])/)&&(b+=5),a.match(/(.*[!,@,#...

    String testString = "abcdef";
    Reader reader = new StringReader(testString);

    assertEquals(testString.charAt(0), reader.read());
    CharStreams.skipFully(reader, 1);
    assertEquals(testString.charAt(2), reader.read());
    CharStreams.skipFully(reader, 2);
    assertEquals(testString.charAt(5), reader.read());

    assertEquals(-1, reader.read());
  }

  public void testAsWriter() {

    String testString = "abcdef";
    Reader reader = new StringReader(testString);

    assertEquals(testString.charAt(0), reader.read());
    CharStreams.skipFully(reader, 1);
    assertEquals(testString.charAt(2), reader.read());
    CharStreams.skipFully(reader, 2);
    assertEquals(testString.charAt(5), reader.read());

    assertEquals(-1, reader.read());
  }

  public void testAsWriter() {

            this.buffer[i] = (short) str.charAt(i);
        }
        if (zterm) {
            this.buffer[i] = (short) 0;
        }
    }

    @Override
    public String toString() {
        final int len = this.length / 2 - (this.zterm ? 1 : 0);
        final char[] ca = new char[len];
        for (int i = 0; i < len; i++) {
            ca[i] = (char) this.buffer[i];
        }

### Casos de uso: servicio externo

Un ejemplo podría ser que tienes un proveedor de autenticación externo al que necesitas llamar.

Le envías un token y te devuelve un usuario autenticado.

Este proveedor podría estar cobrándote por cada request, y llamarlo podría tomar más tiempo adicional que si tuvieras un usuario de prueba fijo para los tests.