Rodrigo B. de Oliveira <******@****.***> <******@****.***>
Sebastian Schuberth <******@****.***> <******@****.***>
Stefan Oehme <******@****.***> <******@****.***>
Sterling Greene <******@****.***> <big******@****.***>
Sterling Greene <******@****.***> <******@****.***>
Szczepan Faber <******@****.***>
Szczepan Faber <******@****.***> <******@****.***>

   * @param numBytes the number of bytes in the byte array
   * @param expectedCount the expected number of roundtrippable permutations
   * @param start the starting bytes encoded as a long as big-endian
   * @param lim the limit of bytes to process encoded as a long as big-endian, or -1 to mean the max
   *     limit for numBytes
   */
  @GwtIncompatible // java.nio.charset.Charset

package tests_test

import (
	"crypto/rand"
	"fmt"
	"gorm.io/gorm/internal/lru"
	"math"
	"math/big"
	"reflect"
	"sync"
	"testing"
	"time"
)

func TestLRU_Add_ExistingKey_UpdatesValueAndExpiresAt(t *testing.T) {
	lru := lru.NewLRU[string, int](10, nil, time.Hour)
	lru.Add("key1", 1)
	lru.Add("key1", 2)

	if value, ok := lru.Get("key1"); !ok || value != 2 {
		t.Errorf("Expected value to be updated to 2, got %v", value)

  // trivial because the divisor is bigger than the dividend.
  // Using remainder here does not give us a uniform distribution but it should
  // not have a big impact on the measurement.
  private static long randomDivisor(long dividend) {
    long r = randomSource.nextLong();
    if (dividend == -1) {
      return r;
    } else {

    checkArgument(
        result == (int) result,
        "the total number of elements (%s) in the arrays must fit in an int",
        result);
    return (int) result;
  }

  /**
   * Returns a big-endian representation of {@code value} in a 2-element byte array; equivalent to
   * {@code ByteBuffer.allocate(2).putChar(value).array()}. For example, the input value {@code

    int bits = LongMath.log2(startingNumber, FLOOR) + 1;
    // Check for the next power of two boundary, to save us a CLZ operation.
    int nextPowerOfTwo = 1 << (bits - 1);

    // Iteratively multiply the longs as big as they can go.
    for (long num = startingNumber; num <= n; num++) {
      // Check to see if the floor(log2(num)) + 1 has changed.
      if ((num & nextPowerOfTwo) != 0) {
        nextPowerOfTwo <<= 1;
        bits++;

import org.apache.maven.api.annotations.Provider;

/**
 * This interface supplies the API for providing feedback to the user from the {@code Mojo},
 * using standard Maven channels.
 * There should be no big surprises here, although you may notice that the methods accept
 * <code>java.lang.CharSequence</code> rather than <code>java.lang.String</code>. This is provided mainly as a

    checkArgument(
        result == (int) result,
        "the total number of elements (%s) in the arrays must fit in an int",
        result);
    return (int) result;
  }

  /**
   * Returns a big-endian representation of {@code value} in a 4-element byte array; equivalent to
   * {@code ByteBuffer.allocate(4).putInt(value).array()}. For example, the input value {@code

          // yes, that's a lot of sinks!
          sinks.add(new Sink(chunkSize, bufferSize));
          // For convenience, testing only with big endianness, to match DataOutputStream.
          // I regard highly unlikely that both the little endianness tests above and this one
          // passes, and there is still a little endianness bug lurking around.
        }

 * short}, {@code int}, {@code float}, {@code double}, and {@code long} values.
 *
 * <p><b>Note:</b> This class intentionally violates the specification of its supertype {@code
 * DataInput}, which explicitly requires big-endian byte order.
 *
 * @author Chris Nokleberg
 * @author Keith Bottner
 * @since 8.0
 */
@J2ktIncompatible
@GwtIncompatible