* elements.
 *
 * <p>The collections created by {@link #createCollection()} may or may not allow duplicates. If the
 * collection, such as a {@link Set}, does not support duplicates, an added key-value pair will
 * replace an existing pair with the same key and value, if such a pair is present. With collections
 * like {@link List} that allow duplicates, the collection will keep the existing key-value pairs
 * while adding a new pair.
 *

        }
        if (elements.length > 0) {
          multiset1.add(elements[0]);
        }
        if (elements.length > 1) {
          /*
           * When a test requests a multiset with duplicates, our plan of
           * "add an extra item 0 to A and an extra item 1 to B" really means
           * "add an extra item 0 to A and B," which isn't what we want.
           */

    public void test_duplicateUrlsInSitemap() {
        // Test handling of duplicate URLs in sitemap
        ResponseData responseData = new ResponseData();
        byte[] content = "<sitemap></sitemap>".getBytes();
        responseData.setResponseBody(content);

        SitemapUrl sitemap1 = new SitemapUrl();
        sitemap1.setLoc("https://example.com/duplicate");

        SitemapUrl sitemap2 = new SitemapUrl();

   * order. The sorting algorithm used is stable, so elements that compare as equal will stay in the
   * order in which they appear in the input.
   *
   * <p>If your data has no duplicates, or you wish to deduplicate elements, use {@code
   * ImmutableSortedSet.copyOf(elements)}; if you want a {@code List} you can use its {@code
   * asList()} view.
   *

  }

  /**
   * {@inheritDoc}
   *
   * <p>The iterator generated by the returned collection traverses the values in the order they
   * were added to the multimap. Because the values may have duplicates and follow the insertion
   * ordering, this method returns a {@link List}, instead of the {@link Collection} specified in
   * the {@link ListMultimap} interface.
   */
  @Override
  public List<V> values() {

        assertTrue(data.getChildUrlSet().contains(child2));
    }

    public void test_childUrlSetNoDuplicates() {
        // Test that child URL set does not allow duplicates
        ResponseData data = new ResponseData();

        RequestData child = new RequestData();
        child.setMethod(Method.GET);
        child.setUrl("https://example.com/page1");

    Map<Integer, String> expected = new LinkedHashMap<>();
    for (int i = 0; i < 1000; i++) {
      // Truncate to even key, so we have put(0, "0") then put(0, "1"). Half the entries are
      // duplicates.
      Integer key = i & ~1;
      String value = String.valueOf(i);
      builder.put(key, value);
      expected.put(key, value);
    }
    ImmutableMap<Integer, String> map = builder.buildKeepingLast();

        urlQueue2.setMethod("GET");
        urlQueue2.setSessionId(sessionId);
        urlQueue2.setUrl("http://www.example.com/page1"); // Duplicate
        urlQueueList.add(urlQueue2);

        urlQueueService.offerAll(sessionId, urlQueueList);

        // Should only store one item (duplicates are filtered)
        int count = 0;
        while (true) {
            final OpenSearchUrlQueue polled = urlQueueService.poll(sessionId);

 * During this process only the most relevant version of each artifact
 * (based on group ID and artifact ID) is retained, resolving conflicts and eliminating duplicates to ensure
 * that each dependency is included only once in the final build.</p>
 *
 * <p><dfn>Dependency resolution</dfn> is the process of collecting dependencies, flattening the result graph,

   * @param columnKeys column keys that may be stored in the generated table
   * @throws NullPointerException if any of the provided keys is null
   * @throws IllegalArgumentException if {@code rowKeys} or {@code columnKeys} contains duplicates
   *     or if exactly one of {@code rowKeys} or {@code columnKeys} is empty.
   */
  public static <R, C, V> ArrayTable<R, C, V> create(
      Iterable<? extends R> rowKeys, Iterable<? extends C> columnKeys) {