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                public void run() {
                    try {
                        startLatch.await();
                        for (int j = 0; j < operationsPerThread; j++) {
                            // Perform various operations
                            crawlerContext.setSessionId("session-" + threadId + "-" + j);
                            crawlerContext.setActiveThreadCount(threadId);

        });
        return asHtml(path_AdminDictStemmeroverride_AdminDictStemmeroverrideJsp).renderWith(data -> {
            searchPaging(data, form);
        });
    }

    /**
     * Perform a search operation for stemmer override items.
     * Updates the pager with search criteria and displays filtered results.
     *
     * @param form The search form containing search criteria

`def` para ter um mínimo ganho de performance (cerca de 100 nanosegundos), por favor observe que no **FastAPI** o efeito pode ser bem o oposto. Nesses casos, é melhor usar `async def` a menos que suas *funções de operação de rota* utilizem código que performe bloqueamento <abbr title="Input/Output – Entrada e Saída: leitura ou escrita no disco, comunicações de rede.">I/O</abbr>.

Ainda, em ambas as situações, as chances são que o **FastAPI** [ainda será mais rápido](index.md#performance){.internal-link...

   * elements, and each pair of corresponding elements is equivalent according to {@code this}. Null
   * iterables are equivalent to one another.
   *
   * <p>Note that this method performs a similar function for equivalences as {@link
   * com.google.common.collect.Ordering#lexicographical} does for orderings.
   *
   * <p>The returned object is serializable if this object is serializable.
   *

     * with each iteration, so this algorithm takes O(log(digits)) iterations.
     *
     * We start out with a double-precision approximation, which may be higher or lower than the
     * true value. Therefore, we perform at least one Newton iteration to get a guess that's
     * definitely >= floor(sqrt(x)), and then continue the iteration until we reach a fixed point.
     */
    BigInteger sqrt0;
    int log2 = log2(x, FLOOR);