* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

package model

import com.fasterxml.jackson.databind.ObjectMapper
import com.fasterxml.jackson.module.kotlin.readValue
import com.fasterxml.jackson.module.kotlin.registerKotlinModule
import java.io.File

val ignoredSubprojects =

  <modelVersion>4.0.0</modelVersion>

  <groupId>inheritance</groupId>
  <artifactId>parent</artifactId>
  <version>11-SNAPSHOT</version>

  <name>Model urls inheritance test parent</name>
  <description>Flat directory structure case: module = ../child directory path + child directory path != child-artifact-id</description>

  <modules>

    <artifactId>parent</artifactId>
    <version>11-SNAPSHOT</version>
  </parent>

  <groupId>inheritance</groupId>
  <artifactId>child-artifact-id</artifactId>
  <version>11-SNAPSHOT</version>
  <name>Model urls inheritance test child</name>
  <description>Flat directory structure case: module = ../child-artifact-id + child directory path != child-artifact-id</description>

    <artifactId>parent</artifactId>
    <version>11-SNAPSHOT</version>
  </parent>

  <groupId>inheritance</groupId>
  <artifactId>child-artifact-id</artifactId>
  <version>11-SNAPSHOT</version>
  <name>Model urls inheritance test child</name>
  <description>Most classical case: child in direct subdirectory with directory name == child artifactId</description>

  <!-- 5 inherited urls with ${project.artifactId} added to parent -->

 * specific language governing permissions and limitations
 * under the License.
 */
package org.apache.maven.model.resolution;

import org.apache.maven.model.Repository;

/**
 * Signals an error when adding a repository to the model resolver.
 *
 * @deprecated use {@code org.apache.maven.api.services.ModelBuilder} instead
 */
@Deprecated(since = "4.0.0")

{* ../../docs_src/response_change_status_code/tutorial001_py310.py hl[1,9,12] *}

And then you can return any object you need, as you normally would (a `dict`, a database model, etc).

And if you declared a `response_model`, it will still be used to filter and convert the object you returned.

    <artifactId>parent</artifactId>
    <version>11-SNAPSHOT</version>
  </parent>

  <groupId>inheritance</groupId>
  <artifactId>inheritance</artifactId>
  <version>11-SNAPSHOT</version>
  <name>Model urls inheritance test child</name>
  <description>MNG-5951 MNG-6059 child.x.y.inherit.append.path="false" for each url to avoid automatic path addition when inheriting</description>

  child.project.url.inherit.append.path="false">
  <modelVersion>4.0.0</modelVersion>

  <groupId>inheritance</groupId>
  <artifactId>parent</artifactId>
  <version>11-SNAPSHOT</version>

  <name>Model urls inheritance test parent</name>
  <description>MNG-5951 MNG-6059 child.x.y.inherit.append.path="false" for each url to avoid automatic path addition when inheriting</description>

  <modules>

"AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
KIND, either express or implied.  See the License for the
specific language governing permissions and limitations
under the License.
-->

<model xmlns="http://codehaus-plexus.github.io/MODELLO/2.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://codehaus-plexus.github.io/MODELLO/2.0.0 https://codehaus-plexus.github.io/modello/xsd/modello-2.0.0.xsd"

<div class="termy">

```console
$ pip install sqlmodel
---> 100%
```

</div>

## 単一モデルでアプリ作成 { #create-the-app-with-a-single-model }

まずは最も簡単な、単一の SQLModel モデルだけを使うバージョンを作ります。

後で、下記のとおり複数モデルにしてセキュリティと汎用性を高めます。🤓

### モデルの作成 { #create-models }

`SQLModel` をインポートしてデータベースモデルを作成します:

{* ../../docs_src/sql_databases/tutorial001_an_py310.py ln[1:11] hl[7:11] *}