* {@link #putString(CharSequence, Charset)} is generally only useful for cross-language
 * compatibility (otherwise prefer {@link #putUnencodedChars}). However, the character encodings
 * must be identical across languages. Also beware that {@link Charset} definitions may occasionally
 * change between Java releases.
 *
 * <p><b>Warning:</b> Chunks of data that are put into the {@link Hasher} are not delimited. The

    Object[] array = collection.toArray();
    expectArrayContentsAnyOrder(createSamplesArray(), array);
  }

  /**
   * {@link Collection#toArray(Object[])} says: "Note that {@code toArray(new Object[0])} is
   * identical in function to {@code toArray()}."
   *
   * <p>For maximum effect, the collection under test should be created from an element array of a
   * type other than {@code Object[]}.
   */

            assertEquals(orderedDialects[i], SMBUtil.readInt2(buffer, 24 + i * 2));
        }
    }

    @Test
    @DisplayName("Test multiple encode calls produce identical output")
    void testMultipleEncodeCallsIdentical() {
        ValidateNegotiateInfoRequest request =

 * even {@code java.util.HashSet}, and places considerably less load on the garbage collector. Like
 * {@code java.util.LinkedHashSet}, it offers insertion-order iteration, with identical behavior.
 *
 * <p>This class should not be assumed to be universally superior to {@code
 * java.util.LinkedHashSet}. Generally speaking, this class reduces object allocation and memory

   * value that are {@linkplain Range#isConnected connected} to this range.
   *
   * <p>The behavior of {@link #get(Comparable) get(k)} after calling this method is identical to
   * the behavior described in {@link #put(Range, Object) put(range, value)}, however the ranges
   * returned from {@link #asMapOfRanges} will be different if there were existing entries which

   * 'affect' a bit(j) in the output if two inputs, identical but for bit(i), will differ at output
   * bit(j) about half the time
   *
   * <p>Funneling is pretty simple to detect. The key idea is to find example keys which
   * unequivocally demonstrate that funneling cannot be occurring. This is done bit-by-bit. For each
   * input bit(i) and output bit(j), two pairs of keys must be found with all bits identical except

         * ours. Therefore, we have to be careful about whether we create our own TypeVariable:
         *
         * 2a. If the resolved types are identical to the original types, then we can return the
         * original, identical JDK TypeVariable. By doing so, we sidestep the problem entirely.
         *
         * 2b. If the resolved types are different from the original types, things are trickier. The

        String slackResult = notificationHelper.toSlackMessage(discloser);
        String googleChatResult = notificationHelper.toGoogleChatMessage(discloser);

        // Both methods should produce identical output
        assertEquals(slackResult, googleChatResult);
    }

    public void test_toSlackMessage_withLongContent() {
        MockSMailPostingDiscloser discloser = new MockSMailPostingDiscloser();

        Boolean result1 = (Boolean) constantTimeMethod.invoke(null, password1, password2);
        Boolean result2 = (Boolean) constantTimeMethod.invoke(null, password1, password3);

        assertTrue(result1, "Identical passwords should be equal");
        assertFalse(result2, "Different passwords should not be equal");
    }

    /**
     * Measure the average time for equals operations.
     */

			if cmp != -1 {
				t.Errorf(`CompareBbigger(%d,%d) = %d`, len, k, cmp)
			}
			b[k] = a[k]
		}
	}
}

func TestEndianBaseCompare(t *testing.T) {
	// This test compares byte slices that are almost identical, except one
	// difference that for some j, a[j]>b[j] and a[j+1]<b[j+1]. If the implementation
	// compares large chunks with wrong endianness, it gets wrong result.
	// no vector register is larger than 512 bytes for now