* products that you would get from nesting for loops:
   *
   * {@snippet :
   * for (B b0 : lists.get(0)) {
   *   for (B b1 : lists.get(1)) {
   *     ...
   *     ImmutableList<B> tuple = ImmutableList.of(b0, b1, ...);
   *     // operate on tuple
   *   }
   * }
   * }
   *
   * <p>Note that if any input list is empty, the Cartesian product will also be empty. If no lists

   * products that you would get from nesting for loops:
   *
   * {@snippet :
   * for (B b0 : lists.get(0)) {
   *   for (B b1 : lists.get(1)) {
   *     ...
   *     ImmutableList<B> tuple = ImmutableList.of(b0, b1, ...);
   *     // operate on tuple
   *   }
   * }
   * }
   *
   * <p>Note that if any input list is empty, the Cartesian product will also be empty. If no lists

    //
    // 1. Subscribers to events posted on different threads can be interleaved with each other
    //    freely. (A event on one thread, B event on another could yield any of
    //    [a1, a2, a3, b1, b2], [a1, b2, a2, a3, b2], [a1, b2, b3, a2, a3], etc.)
    // 2. It's possible for subscribers to actually be dispatched to in a different order than they

      assertThat(it.edit()).isNull()
    }
    assertThat(cache.size()).isEqualTo(0L)
  }

  @Test
  fun iterator() {
    set("a", "a1", "a2")
    set("b", "b1", "b2")
    set("c", "c1", "c2")
    val iterator = cache.snapshots()
    assertThat(iterator.hasNext()).isTrue()
    iterator.next().use {
      assertThat(it.key()).isEqualTo("a")
      it.assertValue(0, "a1")

   * Returns the {@code int} value whose byte representation is the given 4 bytes, in big-endian
   * order; equivalent to {@code Ints.fromByteArray(new byte[] {b1, b2, b3, b4})}.
   *
   * @since 7.0
   */
  public static int fromBytes(byte b1, byte b2, byte b3, byte b4) {
    return b1 << 24 | (b2 & 0xFF) << 16 | (b3 & 0xFF) << 8 | (b4 & 0xFF);
  }

  private static final class IntConverter extends Converter<String, Integer>

   * order; equivalent to {@code Longs.fromByteArray(new byte[] {b1, b2, b3, b4, b5, b6, b7, b8})}.
   *
   * @since 7.0
   */
  public static long fromBytes(
      byte b1, byte b2, byte b3, byte b4, byte b5, byte b6, byte b7, byte b8) {
    return (b1 & 0xFFL) << 56
        | (b2 & 0xFFL) << 48
        | (b3 & 0xFFL) << 40
        | (b4 & 0xFFL) << 32

        PriorityTrackingBooster.clearExecutionOrder();

        scoreUpdater.execute();

        // Due to integer overflow in comparator, execution order is affected for extreme values
        // The comparator b2 - b1 with MAX_VALUE and MIN_VALUE causes overflow
        List<Integer> executionOrder = PriorityTrackingBooster.getExecutionOrder();
        assertEquals(3, executionOrder.size());

            };
    TypeWithDuplicates a = new TypeWithDuplicates(1, 1);
    TypeWithDuplicates b1 = new TypeWithDuplicates(2, 1);
    TypeWithDuplicates b2 = new TypeWithDuplicates(2, 2);
    TypeWithDuplicates c = new TypeWithDuplicates(3, 1);
    CollectorTester.of(collector, equivalence)
        .expectCollects(ImmutableSortedSet.of(a, b1, c), a, b1, c, b2);
  }

  public void testEquals_bothDefaultOrdering() {

        // TODO use newest conflict resolver
        ArtifactSpec a = createArtifactSpec("a", "1.0");
        ArtifactSpec b1 = a.addDependency("b", "1.0");
        ArtifactSpec c = a.addDependency("c", "1.0");
        ArtifactSpec d2 = b1.addDependency("d", "2.0");
        d2.addDependency("h", "1.0");
        ArtifactSpec d1 = c.addDependency("d", "1.0");

   * products that you would get from nesting for loops:
   *
   * {@snippet :
   * for (B b0 : sets.get(0)) {
   *   for (B b1 : sets.get(1)) {
   *     ...
   *     ImmutableList<B> tuple = ImmutableList.of(b0, b1, ...);
   *     // operate on tuple
   *   }
   * }
   * }
   *