"Kubernetes configuration file")
	flags.StringVar(r.configContext, FlagContext, "",
		"Kubernetes configuration context")
	flags.StringVar(r.impersonate, FlagImpersonate, *r.impersonate,
		"Username to impersonate for the operation. User could be a regular user or a service account in a namespace")
	flags.StringVar(r.impersonateUID, FlagImpersonateUID, *r.impersonateUID, "UID to impersonate for the operation.")

Bevorzugen Sie die `Annotated`-Version, falls möglich.

///

```Python hl_lines="105  107-115"
{!> ../../docs_src/security/tutorial005.py!}
```

////

## Den `username` und das Format der Daten überprüfen

Wir verifizieren, dass wir einen `username` erhalten, und extrahieren die Scopes.

        uses: actions/setup-java@8df1039502a15bceb9433410b1a100fbe190c53b # v4.5.0
        with:
          java-version: 21
          distribution: 'zulu'
          server-id: sonatype-nexus-snapshots
          server-username: CI_DEPLOY_USERNAME
          server-password: CI_DEPLOY_PASSWORD
          cache: 'maven'
      - name: 'Publish'
        env:
          CI_DEPLOY_USERNAME: ${{ secrets.CI_DEPLOY_USERNAME }}

そして、セキュリティ要件のためにどんなモデルやデータでも利用することができます。（この場合は、 Pydanticモデルの `User`）

しかし、特定のデータモデルやクラス、型に制限されることはありません。

モデルを、 `id` と `email` は持つが、 `username` は全く持たないようにしたいですか？ わかりました。同じ手段でこうしたこともできます。

ある `str` だけを持ちたい？ あるいはある `dict` だけですか？ それとも、データベースクラスのモデルインスタンスを直接持ちたいですか？ すべて同じやり方で機能します。

    val url: URL = httpUrl.url()
    val uri: URI = httpUrl.uri()
    val scheme: String = httpUrl.scheme()
    val encodedUsername: String = httpUrl.encodedUsername()
    val username: String = httpUrl.username()
    val encodedPassword: String = httpUrl.encodedPassword()
    val password: String = httpUrl.password()
    val host: String = httpUrl.host()
    val port: Int = httpUrl.port()

minio server ~/test
```

Create new users following the multi-user guide [here](https://min.io/docs/minio/linux/administration/identity-access-management.html)

### Testing an example with awscli tool

> Use the same username and password created in the previous steps.

```
[foobar]
region = us-east-1
aws_access_key_id = foobar
aws_secret_access_key = foo12345
```

			Key:         KafkaTopic,
			Description: "Kafka topic used for bucket notifications",
			Optional:    true,
			Type:        "string",
		},
		config.HelpKV{
			Key:         KafkaSASLUsername,
			Description: "username for SASL/PLAIN or SASL/SCRAM authentication",
			Optional:    true,
			Type:        "string",
			Sensitive:   true,
		},
		config.HelpKV{
			Key:         KafkaSASLPassword,

            doColumn("updatedBy");
        }

        public void columnUpdatedTime() {
            doColumn("updatedTime");
        }

        public void columnUsername() {
            doColumn("username");
        }

        public void columnWebConfigId() {
            doColumn("webConfigId");
        }
    }

```

////

Caso um cliente tente enviar informações adicionais, ele receberá um retorno de **erro**.

Por exemplo, se o cliente tentar enviar os campos de formulário:

* `username`: `Rick`
* `password`: `Portal Gun`
* `extra`: `Mr. Poopybutthole`

Ele receberá um retorno de erro informando-o que o campo `extra` não é permitido:

```json
{
    "detail": [
        {

        The {@code <server>} element contains information required to a server settings.
      </description>
      <fields>
        <field>
          <name>username</name>
          <version>1.0.0+</version>
          <description>
            The username used to authenticate.
          </description>
          <type>String</type>
        </field>
        <field>
          <name>password</name>