}

    /**
     * Configures this {@code Builder} to order entries by value according to the specified
     * comparator.
     *
     * <p>The sort order is stable, that is, if two entries have values that compare as equivalent,
     * the entry that was inserted first will be first in the built map's iteration order.
     *
     * @throws IllegalStateException if this method was already called
     * @since 19.0
     */

  @Generates
  <T extends @Nullable Object> Ordering<T> generateOrdering() {
    return new Ordering<T>() {
      @Override
      @SuppressWarnings("UnusedVariable") // intentionally weird Comparator
      public int compare(T left, T right) {
        return 0;
      }

      final String string = paramString(Ordering.class, generateInt());

      @Override
      public String toString() {
        return string;
      }

  }

  private static final class DecreasingCount implements Comparator<Entry<?>> {
    static final Comparator<Entry<?>> INSTANCE = new DecreasingCount();

    @Override
    public int compare(Entry<?> entry1, Entry<?> entry2) {
      return entry2.getCount() - entry1.getCount(); // subtracting two nonnegative integers
    }
  }

  /**

  }

  private static final class DecreasingCount implements Comparator<Entry<?>> {
    static final Comparator<Entry<?>> INSTANCE = new DecreasingCount();

    @Override
    public int compare(Entry<?> entry1, Entry<?> entry2) {
      return entry2.getCount() - entry1.getCount(); // subtracting two nonnegative integers
    }
  }

  /**

  /**
   * Returns an {@code ImmutableSortedSet} containing all of the elements from this {@code
   * FluentIterable} in the order specified by {@code comparator}, with duplicates (determined by
   * {@code comparator.compare(x, y) == 0}) removed. To produce an {@code ImmutableSortedSet} sorted
   * by its natural ordering, use {@code toSortedSet(Ordering.natural())}.
   *

Linux containers run using the same Linux kernel of the host (machine, virtual machine, cloud server, etc). This just means that they are very lightweight (compared to full virtual machines emulating an entire operating system).

This way, containers consume **little resources**, an amount comparable to running the processes directly (a virtual machine would consume much more).

	if r == 0 {
		r = reseed()
	}
	// constants from Numerical Recipes
	r = r*1664525 + 1013904223
	randN = r
	randmu.Unlock()
	return strconv.Itoa(int(1e9 + r%1e9))[1:]
}

// isSameType - compares two object types via reflect.TypeOf
func isSameType(obj1, obj2 any) bool {
	return reflect.TypeOf(obj1) == reflect.TypeOf(obj2)
}

     * hashcode.
     */

    @Override
    public int hashCode() {
        return address;
    }

    /**
     * Determines if this address is equal two another. Only the IP Addresses
     * are compared. Similar to the {@link #hashCode} method, the comparison
     * is based on the integer IP address and not the string representation.
     */

    @Override
    public boolean equals(final Object obj) {

		oVer := oVers.versions[i]
		if eVer.header != oVer.header {
			if eVer.header.hasEC() != oVer.header.hasEC() {
				// One version has EC and the other doesn't - may have been written later.
				// Compare without considering EC.
				a, b := eVer.header, oVer.header
				a.EcN, a.EcM = 0, 0
				b.EcN, b.EcM = 0, 0
				if a == b {
					continue
				}
			}

		},
		{
			name:       "compare-mixed",
			query:      `SELECT id from s3object s WHERE value = true`,
			wantResult: `{"id":1}`,
			withJSON: `{"id":0, "value": false}
{"id":1, "value": true}
{"id":2, "value": 42}
{"id":3, "value": "true"}
`,
		},
		{
			name:       "compare-mixed-not",
			query:      `SELECT COUNT(id) as n from s3object s WHERE value != true`,