cmdList.add("-D" + Constants.FESS_SEARCH_ENGINE_HTTP_ADDRESS + "=" + httpAddress);
            }
        }

        final String systemLastaEnv = System.getProperty("lasta.env");
        if (StringUtil.isNotBlank(systemLastaEnv)) {
            if ("web".equals(systemLastaEnv)) {
                cmdList.add("-Dlasta.env=" + getExecuteType());
            } else {

    /** The key of the message: Last Modified (ascending) */
    public static final String LABELS_search_result_sort_last_modified_asc = "{labels.search_result_sort_last_modified_asc}";

    /** The key of the message: Last Modified (descending) */

      SortedSet<C> set = (SortedSet<C>) values;
      Comparator<?> comparator = set.comparator();
      if (Ordering.<C>natural().equals(comparator) || comparator == null) {
        return closed(set.first(), set.last());
      }
    }
    Iterator<C> valueIterator = values.iterator();
    C min = checkNotNull(valueIterator.next());
    C max = min;
    while (valueIterator.hasNext()) {

         * enough. Consider, for example, the case where we have a buffer of size (n+1), add n
         * distinct elements, and add the last element over again many times over. We don't want a
         * situation where we re-sort the entire buffer every time the last element is re-added.
         *
         * <p>The solution is to ensure there are O(n) spaces left over in the buffer after

  public void testObjectHashCodeWithSameLowOrderBytes() {
    // These will have the same first 4 bytes (all 0).
    byte[] bytesA = new byte[5];
    byte[] bytesB = new byte[5];

    // Change only the last (5th) byte
    bytesA[4] = (byte) 0xbe;
    bytesB[4] = (byte) 0xef;

    HashCode hashCodeA = HashCode.fromBytes(bytesA);
    HashCode hashCodeB = HashCode.fromBytes(bytesB);

    // They aren't equal...

    if (!couldBeProperty && !couldBeExtensionProperty) {
        return emptyList()
    }

    val propertyJavaType =
        if (hasGetterName) method.returnType.name
        else method.parameterTypes.last().name

    val isBoolean =
        primitiveTypeStrings[propertyJavaType] == Boolean::class.simpleName

    val propertyNames =
        if (hasIsGetterName) listOf(method.name)
        else {

	}

	// Do not send if the connection is not active.
	_, err := target.isActive()
	if err != nil {
		return err
	}

	eventData, err := target.store.Get(key)
	if err != nil {
		// The last event key in a successful batch will be sent in the channel atmost once by the replayEvents()
		// Such events will not exist and wouldve been already been sent successfully.
		if os.IsNotExist(err) {
			return nil
		}

- Temporary credentials are short-term, as the name implies. They can be configured to last for anywhere from a few minutes to several hours. After the credentials expire, MinIO no longer recognizes them or allows any kind of access from API requests made with them.

    this.chunkSize = chunkSize;
  }

  /** Processes the available bytes of the buffer (at most {@code chunk} bytes). */
  protected abstract void process(ByteBuffer bb);

  /**
   * This is invoked for the last bytes of the input, which are not enough to fill a whole chunk.
   * The passed {@code ByteBuffer} is guaranteed to be non-empty.
   *
   * <p>This implementation simply pads with zeros and delegates to {@link #process(ByteBuffer)}.

   * when hasNext() is false, so that next() throws a NoSuchElementException, then subsequent calls
   * to remove() will incorrectly throw an IllegalStateException, instead of removing the last
   * element returned.
   *
   * <p>See <a href="http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=6529795">Sun bug 6529795</a>
   */
  static class IteratorWithSunJavaBug6529795<T> implements Iterator<T> {