*
 * Regular lines contain fields separated by semicolons.
 *
 * The first element on each line is a single hex code point (like 0041) or a hex code point range
 * (like 0030..0039).
 *
 * The second element on each line is a mapping type, like `valid` or `mapped`.
 *
 * For lines that contain a mapping target, the next thing is a sequence of hex code points (like
 * 0031 2044 0034).
 *
 * All other data is ignored.

    //    were added to the queue. It's easily possible for one thread to take the head of the
    //    queue, immediately followed by another thread taking the next element in the queue. That
    //    second thread can then dispatch to the subscriber it took before the first thread does.
    //
    // All this makes me really wonder if there's any value in queueing here at all. A dispatcher

            if (exitValue != 0) {
                final StringBuilder out = new StringBuilder();
                if (processTimeout) {
                    out.append("Process is terminated due to ").append(timeout).append(" second exceeded.\n");
                }
                out.append("Exit Code: ").append(exitValue).append("\nOutput:\n").append(it.getOutput());
                throw new JobProcessingException(out.toString());
            }

		return
	}

	durationStr := r.Form.Get(peerRESTDuration)
	duration, err := time.ParseDuration(durationStr)
	if err != nil || duration.Seconds() == 0 {
		duration = time.Second * 10
	}
	result := netperf(r.Context(), duration.Round(time.Second))
	peersLogIf(r.Context(), gob.NewEncoder(w).Encode(result))
}

	m.percUtil = float64(ioStats.TotalTicks) * 100 / (durationSecs * 1000)

	return
}

func newDriveMetricsCache() *cachevalue.Cache[storageMetrics] {
	var (
		// prevDriveIOStats is used to calculate "per second"
		// values for IOStat related disk metrics e.g. reads/sec.
		prevDriveIOStats            map[string]madmin.DiskIOStats
		prevDriveIOStatsMu          sync.RWMutex
		prevDriveIOStatsRefreshedAt time.Time
	)

    /**
     * Returns whether two strings are equal. If both are null, returns <code>true</code>.
     *
     * @param target1
     *            the first string
     * @param target2
     *            the second string
     * @return true if the strings are equal, false otherwise
     */
    public static boolean equals(final String target1, final String target2) {

            // this will run at most twice. The first time, the firstRun flag is turned off, and if the retry flag
            // is set on the first run, it will be turned off and not re-set on the second try. This is because the
            // only way the retry flag can be set is if ( firstRun == true ).
            while (firstRun || retry) {
                ChecksumObserver md5ChecksumObserver = null;

        Field remarkField = SmbShareInfo.class.getDeclaredField("remark");
        remarkField.setAccessible(true);
        assertEquals("Remark for Share1", remarkField.get(shareInfo));

        // Verify the second entry
        FileEntry entry2 = entries[1];
        assertNotNull(entry2);
        assertEquals("Share2", entry2.getName());
        assertEquals(32, entry2.getType()); // TYPE_PRINTER constant (0x20)
    }

#### Um ataque "profissional"

Claro, os invasores não tentariam tudo isso de forma manual, eles escreveriam um programa para fazer isso, possivelmente com milhares ou milhões de testes por segundo. E obteriam apenas uma letra a mais por vez.

Mas fazendo isso, em alguns minutos ou horas os invasores teriam adivinhado o usuário e senha corretos, com a "ajuda" da nossa aplicação, apenas usando o tempo levado para responder.

        long time = System.currentTimeMillis();
        ServerMessageBlock.writeTime(time, buffer, 0);
        long readTime = ServerMessageBlock.readTime(buffer, 0);
        // Precision may be lost, so check within a second
        assertTrue(Math.abs(time - readTime) < 1000);
    }

    @Test
    void testTimeReadWriteZero() {
        byte[] buffer = new byte[8];
        ServerMessageBlock.writeTime(0, buffer, 0);