assertEquals(BigIntegerMath.log10(valueOf(x), mode), IntMath.log10(x, mode));
      }
    }
  }

  // Relies on the correctness of log10(int, FLOOR) and of pow(int, int).
  @GwtIncompatible // pow()
  public void testLog10Exact() {
    for (int x : POSITIVE_INTEGER_CANDIDATES) {
      int floor = IntMath.log10(x, FLOOR);
      boolean expectSuccess = IntMath.pow(10, floor) == x;

TEXT ·log10TrampolineSetup(SB), NOSPLIT, $0
	MOVB   ·hasVX(SB), R1
	CMPBEQ R1, $1, vectorimpl                 // vectorfacility = 1, vector supported
	MOVD   $·log10vectorfacility+0x00(SB), R1
	MOVD   $·log10(SB), R2
	MOVD   R2, 0(R1)
	BR     ·log10(SB)

vectorimpl:
	MOVD $·log10vectorfacility+0x00(SB), R1
	MOVD $·log10Asm(SB), R2
	MOVD R2, 0(R1)
	BR   ·log10Asm(SB)

GLOBL ·log10vectorfacility+0x00(SB), NOPTR, $8

}

// Op: Log1p()
// Summary: Computes natural logarithm of (1 + x) element-wise.
//
// Description:
//   I.e., \\(y = \log_e (1 + x)\\).
//
//   Example:
//
//   ```python
//   x = tf.constant([0, 0.5, 1, 5])
//   tf.math.log1p(x) ==> [0., 0.4054651, 0.6931472, 1.7917595]
//   ```
Status Log1p(AbstractContext* ctx, AbstractTensorHandle* const x,

	for i := 0; i < len(vf); i++ {
		a := Abs(vf[i])
		if f := Log10(a); !veryclose(log10[i], f) {
			t.Errorf("Log10(%g) = %g, want %g", a, f, log10[i])
		}
	}
	if f := Log10(E); f != Log10E {
		t.Errorf("Log10(%g) = %g, want %g", E, f, Log10E)
	}
	for i := 0; i < len(vflogSC); i++ {
		if f := Log10(vflogSC[i]); !alike(logSC[i], f) {
			t.Errorf("Log10(%g) = %g, want %g", vflogSC[i], f, logSC[i])
		}
	}
}

      int j = i & ARRAY_MASK;
      tmp += IntMath.log2(positive[j], mode);
    }
    return tmp;
  }

  @Benchmark
  int log10(int reps) {
    int tmp = 0;
    for (int i = 0; i < reps; i++) {
      int j = i & ARRAY_MASK;
      tmp += IntMath.log10(positive[j], mode);
    }
    return tmp;
  }

  @Benchmark
  int sqrt(int reps) {
    int tmp = 0;
    for (int i = 0; i < reps; i++) {

      int j = i & ARRAY_MASK;
      tmp += BigIntegerMath.log2(positive[j], mode);
    }
    return tmp;
  }

  @Benchmark
  int log10(int reps) {
    int tmp = 0;
    for (int i = 0; i < reps; i++) {
      int j = i & ARRAY_MASK;
      tmp += BigIntegerMath.log10(positive[j], mode);
    }
    return tmp;
  }

  @Benchmark
  int sqrt(int reps) {
    int tmp = 0;
    for (int i = 0; i < reps; i++) {

      int j = i & ARRAY_MASK;
      tmp += BigIntegerMath.log2(positive[j], mode);
    }
    return tmp;
  }

  @Benchmark
  int log10(int reps) {
    int tmp = 0;
    for (int i = 0; i < reps; i++) {
      int j = i & ARRAY_MASK;
      tmp += BigIntegerMath.log10(positive[j], mode);
    }
    return tmp;
  }

  @Benchmark
  int sqrt(int reps) {
    int tmp = 0;
    for (int i = 0; i < reps; i++) {

        assertEquals(BigIntegerMath.log10(valueOf(x), mode), LongMath.log10(x, mode));
      }
    }
  }

  // Relies on the correctness of log10(long, FLOOR) and of pow(long, int).
  @GwtIncompatible // TODO
  public void testLog10Exact() {
    for (long x : POSITIVE_LONG_CANDIDATES) {
      int floor = LongMath.log10(x, FLOOR);
      boolean expectedSuccess = LongMath.pow(10, floor) == x;

  // Relies on the correctness of log10(BigInteger, {HALF_UP,HALF_DOWN}).
  @GwtIncompatible // TODO
  public void testLog10HalfEven() {
    for (BigInteger x : POSITIVE_BIGINTEGER_CANDIDATES) {
      int halfEven = BigIntegerMath.log10(x, HALF_EVEN);
      // Now figure out what rounding mode we should behave like (it depends if FLOOR was
      // odd/even).
      boolean floorWasEven = (BigIntegerMath.log10(x, FLOOR) & 1) == 0;

      int j = i & ARRAY_MASK;
      tmp += LongMath.log2(positive[j], mode);
    }
    return tmp;
  }

  @Benchmark
  int log10(int reps) {
    int tmp = 0;
    for (int i = 0; i < reps; i++) {
      int j = i & ARRAY_MASK;
      tmp += LongMath.log10(positive[j], mode);
    }
    return tmp;
  }

  @Benchmark
  int sqrt(int reps) {
    int tmp = 0;
    for (int i = 0; i < reps; i++) {