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docs/pt/docs/tutorial/security/first-steps.md
Se ele não ver o header de `Autorização` ou o valor não tem um token `Bearer`, vai responder com um código de erro 401 (`UNAUTHORIZED`) diretamente. Você nem precisa verificar se o token existe para retornar um erro. Você pode ter certeza de que se a sua função for executada, ela terá um `str` nesse token.
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Sun Oct 06 20:36:54 UTC 2024 - 8.4K bytes - Viewed (0) -
docs/de/docs/tutorial/security/first-steps.md
Wenn es keinen `Authorization`-Header sieht, oder der Wert keinen `Bearer`-Token hat, antwortet es direkt mit einem 401-Statuscode-Error (`UNAUTHORIZED`). Sie müssen nicht einmal prüfen, ob der Token existiert, um einen Fehler zurückzugeben. Seien Sie sicher, dass Ihre Funktion, wenn sie ausgeführt wird, ein `str` in diesem Token enthält.
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docs/zh/docs/tutorial/security/first-steps.md
/// ## 实现的操作 FastAPI 校验请求中的 `Authorization` 请求头,核对请求头的值是不是由 `Bearer ` + 令牌组成, 并返回令牌字符串(`str`)。 如果没有找到 `Authorization` 请求头,或请求头的值不是 `Bearer ` + 令牌。FastAPI 直接返回 401 错误状态码(`UNAUTHORIZED`)。 开发者不需要检查错误信息,查看令牌是否存在,只要该函数能够执行,函数中就会包含令牌字符串。 正如下图所示,API 文档已经包含了这项功能: <img src="/img/tutorial/security/image03.png"> 目前,暂时还没有实现验证令牌是否有效的功能,不过后文很快就会介绍的。 ## 小结
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Sun Oct 06 20:36:54 UTC 2024 - 7.3K bytes - Viewed (0) -
docs/zh/docs/tutorial/security/simple-oauth2.md
因此,在端点中,只有当用户存在、通过身份验证、且状态为激活时,才能获得该用户: ```Python hl_lines="58-67 69-72 90" {!../../docs_src/security/tutorial003.py!} ``` /// info | "说明" 此处返回值为 `Bearer` 的响应头 `WWW-Authenticate` 也是规范的一部分。 任何 401**UNAUTHORIZED**HTTP(错误)状态码都应返回 `WWW-Authenticate` 响应头。 本例中,因为使用的是 Bearer Token,该响应头的值应为 `Bearer`。 实际上,忽略这个附加响应头,也不会有什么问题。 之所以在此提供这个附加响应头,是为了符合规范的要求。 说不定什么时候,就有工具用得上它,而且,开发者或用户也可能用得上。 这就是遵循标准的好处……
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src/main/resources/fess_message.properties
errors.failed_to_read_request_file=Failed to read request file: {0} errors.invalid_header_for_request_file=Invalid header: {0} errors.could_not_delete_logged_in_user=Could not delete logged in user. errors.unauthorized_request=Unauthorized request. errors.failed_to_print_thread_dump=Failed to print thread dump. errors.file_is_not_supported={0} is not supported. errors.plugin_file_is_not_found={0} is not found.
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src/main/resources/fess_message_en.properties
errors.failed_to_read_request_file=Failed to read request file: {0} errors.invalid_header_for_request_file=Invalid header: {0} errors.could_not_delete_logged_in_user=Could not delete logged in user. errors.unauthorized_request=Unauthorized request. errors.failed_to_print_thread_dump=Failed to print thread dump. errors.file_is_not_supported={0} is not supported. errors.plugin_file_is_not_found={0} is not found.
Registered: Thu Oct 31 13:40:30 UTC 2024 - Last Modified: Sat Mar 18 03:05:44 UTC 2023 - 12.4K bytes - Viewed (0) -
docs/ko/docs/tutorial/security/simple-oauth2.md
```Python hl_lines="55-64 67-70 88" {!> ../../docs_src/security/tutorial003_py310.py!} ``` //// /// 정보 여기서 반환하는 값이 `Bearer`인 추가 헤더 `WWW-Authenticate`도 사양의 일부입니다. 모든 HTTP(오류) 상태 코드 401 "UNAUTHORIZED"는 `WWW-Authenticate` 헤더도 반환해야 합니다. 베어러 토큰의 경우(지금의 경우) 해당 헤더의 값은 `Bearer`여야 합니다. 실제로 추가 헤더를 건너뛸 수 있으며 여전히 작동합니다. 그러나 여기에서는 사양을 준수하도록 제공됩니다.
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docs/pt/docs/tutorial/security/simple-oauth2.md
``` //// /// info | Informação O cabeçalho adicional `WWW-Authenticate` com valor `Bearer` que estamos retornando aqui também faz parte da especificação. Qualquer código de status HTTP (erro) 401 "UNAUTHORIZED" também deve retornar um cabeçalho `WWW-Authenticate`. No caso de tokens ao portador (nosso caso), o valor desse cabeçalho deve ser `Bearer`. Na verdade, você pode pular esse cabeçalho extra e ainda funcionaria.
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docs/ja/docs/tutorial/security/first-steps.md
/// ## どのように動作するか リクエストの中に`Authorization`ヘッダーを探しに行き、その値が`Bearer`と何らかのトークンを含んでいるかどうかをチェックし、そのトークンを`str`として返します。 もし`Authorization`ヘッダーが見つからなかったり、値が`Bearer`トークンを持っていなかったりすると、401 ステータスコードエラー (`UNAUTHORIZED`) で直接応答します。 トークンが存在するかどうかをチェックしてエラーを返す必要はありません。関数が実行された場合、そのトークンに`str`が含まれているか確認できます。 インタラクティブなドキュメントですでに試すことができます: <img src="/img/tutorial/security/image03.png">
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docs/LICENSE
use of the trademark "Creative Commons" or any other trademark or logo of Creative Commons without its prior written consent including, without limitation, in connection with any unauthorized modifications to any of its public licenses or any other arrangements, understandings, or agreements concerning use of licensed material. For the avoidance of doubt, this paragraph does not form part of the
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