<la:message key="labels.dict_kuromoji_title"/>
                        </h1>
                    </div>
                    <div class="col-sm-6">
                        <ol class="breadcrumb float-sm-right">
                            <li class="breadcrumb-item"><la:link href="/admin/dict">
                                <la:message key="labels.dict_list_link"/>
                            </la:link></li>

<div style="text-align: right; margin-right: 10%;">Kabir Khan - <strong>Microsoft</strong> <a href="https://github.com/fastapi/fastapi/pull/26"><small>(ref)</small></a></div>

---

"_**predictions** almak için sorgulanabilecek bir **REST** server oluşturmak amacıyla **FastAPI** kütüphanesini benimsedik. [Ludwig için]_"

<div style="text-align: right; margin-right: 10%;">Kabir Khan - <strong>Microsoft</strong> <a href="https://github.com/fastapi/fastapi/pull/26"><small>(ref)</small></a></div>

---

"_We adopted the **FastAPI** library to spawn a **REST** server that can be queried to obtain **predictions**. [for Ludwig]_"

      successor(pred(), succ());
      if (left == null) {
        return right;
      } else if (right == null) {
        return left;
      } else if (left.height >= right.height) {
        AvlNode<E> newTop = pred();
        // newTop is the maximum node in my left subtree
        newTop.left = left.removeMax(newTop);
        newTop.right = right;
        newTop.distinctElements = distinctElements - 1;

!==s||p.length===d+1)return e;n=e.placement.split('-')[0],i=T(n);var a=e.offsets.popper,l=e.offsets.reference,f=Z,m='left'===n&&f(a.right)>f(l.left)||'right'===n&&f(a.left)<f(l.right)||'top'===n&&f(a.bottom)>f(l.top)||'bottom'===n&&f(a.top)<f(l.bottom),h=f(a.left)<f(o.left),c=f(a.right)>f(o.right),g=f(a.top)<f(o.top),u=f(a.bottom)>f(o.bottom),b='left'===n&&h||'right'===n&&c||'top'===n&&g||'bottom'===n&&u,w=-1!==['top','bottom'].indexOf(n),y=!!t.flipVariations&&(w&&'start'===r&&h||w&&'end'===r&&c...

    int left = 0;
    int right = 2 * k - 1;

    int minThresholdPosition = 0;
    // The leftmost position at which the greatest of the k lower elements
    // -- the new value of threshold -- might be found.

    int iterations = 0;
    int maxIterations = IntMath.log2(right - left, RoundingMode.CEILING) * 3;
    while (left < right) {
      int pivotIndex = (left + right + 1) >>> 1;

  @Override
  @SuppressWarnings("unchecked") // TODO(kevinb): the right way to explain this??
  public int compare(Comparable<?> left, Comparable<?> right) {
    checkNotNull(left); // for GWT
    checkNotNull(right);
    return ((Comparable<Object>) left).compareTo(right);
  }

  @Override
  @SuppressWarnings("unchecked") // TODO(kevinb): the right way to explain this??

  @Override
  @SuppressWarnings("unchecked") // TODO(kevinb): the right way to explain this??
  public int compare(Comparable<?> left, Comparable<?> right) {
    checkNotNull(left); // for GWT
    checkNotNull(right);
    return ((Comparable<Object>) left).compareTo(right);
  }

  @Override
  @SuppressWarnings("unchecked") // TODO(kevinb): the right way to explain this??

                                </div>
                                <div class="form-group row">
                                    <label for="name" class="col-sm-3 text-sm-right col-form-label"><la:message
                                            key="labels.scheduledjob_name"/></label>
                                    <div class="col-sm-9">

    this.ordering = ordering;
  }

  @Override
  public int compare(@Nullable T left, @Nullable T right) {
    if (left == right) {
      return 0;
    }
    if (left == null) {
      return RIGHT_IS_GREATER;
    }
    if (right == null) {
      return LEFT_IS_GREATER;
    }
    return ordering.compare(left, right);
  }

  @Override