// and include err.Num = s.
//
// If s is not syntactically well-formed, ParseComplex returns err.Err = ErrSyntax.
//
// If s is syntactically well-formed but either component is more than 1/2 ULP
// away from the largest floating point number of the given component's size,
// ParseComplex returns err.Err = ErrRange and c = ±Inf for the respective component.
func ParseComplex(s string, bitSize int) (complex128, error) {
	size := 64

// It is not guaranteed to return the largest such n.
func (f Form) QuickSpan(b []byte) int {
	n, _ := formTable[f].quickSpan(inputBytes(b), 0, len(b), true)
	return n
}

// Span implements transform.SpanningTransformer. It returns a boundary n such
// that b[0:n] == f(b[0:n]). It is not guaranteed to return the largest such n.
func (f Form) Span(b []byte, atEOF bool) (n int, err error) {

	if first > last {
		return &biasedSparseMap{first: math.MaxInt32, s: nil}
	}
	return &biasedSparseMap{first: first, s: newSparseMap(1 + last - first)}
}

// cap returns one more than the largest key valid for s
func (s *biasedSparseMap) cap() int {
	if s == nil || s.s == nil {
		return 0
	}
	return s.s.cap() + int(s.first)
}

// size returns the number of entries stored in s

 * dependencies to projects in lower layers. The sizes of different layers are created so that
 * the first and last layers are the smallest and the layers in the middle are the largest.
 *
 * For example when numberOfProjects = 150, 10 layers will be created with sizes of
 * [1, 2, 6, 16, 50, 50, 16, 6, 2, 1]
 *

	return j, z * PI4
}

// mPi4 is the binary digits of 4/pi as a uint64 array,
// that is, 4/pi = Sum mPi4[i]*2^(-64*i)
// 19 64-bit digits and the leading one bit give 1217 bits
// of precision to handle the largest possible float64 exponent.
var mPi4 = [...]uint64{
	0x0000000000000001,
	0x45f306dc9c882a53,
	0xf84eafa3ea69bb81,
	0xb6c52b3278872083,
	0xfca2c757bd778ac3,
	0x6e48dc74849ba5c0,
	0x0c925dd413a32439,

	return resource.ParseQuantity(pageSize)
}

// HugePageUnitSizeFromByteSize returns hugepage size has the format.
// `size` must be guaranteed to divisible into the largest units that can be expressed.
// <size><unit-prefix>B (1024 = "1KB", 1048576 = "1MB", etc).
func HugePageUnitSizeFromByteSize(size int64) (string, error) {

		// the lowest bucket was based around the 180ns/op figure for BenchmarkAccess,
		// plus some additional leeway to account for the apiserver doing other things
		// the largest bucket was chosen based on the fact that benchmarks indicate the
		// same Xeon running a CEL expression close to the estimated cost limit takes
		// around 760ms, so that bucket should only ever have the slowest CEL expressions

			got := r.Eq(s)
			want := in(r, s) == nil && in(s, r) == nil
			if got != want {
				t.Errorf("Eq: r=%s, s=%s: got %t, want %t", r, s, got, want)
			}
		}
	}

	// The intersection should be the largest rectangle a such that every point
	// in a is both in r and in s.
	for _, r := range rects {
		for _, s := range rects {
			a := r.Intersect(s)
			if err := in(a, r); err != nil {

divides the drives you provide into erasure-coding sets of *2 to 16* drives.  Therefore, the number of drives you present must be a multiple of one of these numbers.  Each object is written to a single erasure-coding set.

Minio uses the largest possible EC set size which divides into the number of drives given. For example, *18 drives* are configured as *2 sets of 9 drives*, and *24 drives* are configured as *2 sets of 12 drives*.  This is true for scenarios when running MinIO as a standalone...

// For example, for deckSize=128 and handSize=4 this function might call pick(14); pick(73); pick(119); pick(26).
func (d *Dealer) Deal(hashValue uint64, pick func(int)) {
	// 15 is the largest possible value of handSize
	var remainders [15]int

	for i := 0; i < d.handSize; i++ {
		hashValueNext := hashValue / uint64(d.deckSize-i)
		remainders[i] = int(hashValue - uint64(d.deckSize-i)*hashValueNext)