* Generation, described in Knuth's "The Art of Computer Programming", Volume 4, Chapter 7,
   * Section 7.2.1.2. The iteration order follows the lexicographical order. This means that the
   * first permutation will be in ascending order, and the last will be in descending order.
   *
   * <p>Duplicate elements are considered equal. For example, the list [1, 1] will have only one

                return delegate.createArray(length);
              }

              @Override
              public Iterable<E> order(List<E> insertionOrder) {
                List<E> list = new ArrayList<>();
                for (E e : delegate.order(insertionOrder)) {
                  list.add(e);
                }
                Collections.reverse(list);
                return list;
              }

                        new SafeTreeSet<String>(asList(elements)));
                  }

                  @Override
                  public List<String> order(List<String> insertionOrder) {
                    return new ArrayList<>(Sets.newTreeSet(insertionOrder));
                  }
                })

// 2. String. Name of object. Directories contains a trailing slash.
// 3. Binary. Blob of metadata. Length 0 on directories.
// ... Next element.
//
// Streams can be assumed to be sorted in ascending order.
// If the stream ends before a false boolean it can be assumed it was truncated.

const metacacheStreamVersion = 2

// metacacheWriter provides a serializer of metacache objects.
type metacacheWriter struct {

   *   {@code List<ListenableFuture<T>> futures = (List) executor.invokeAll(tasks);}
   * </pre>
   *
   * @return A list of {@code ListenableFuture} instances representing the tasks, in the same
   *     sequential order as produced by the iterator for the given task list, each of which has
   *     completed.
   * @throws RejectedExecutionException {@inheritDoc}
   * @throws NullPointerException if any task is null
   */
  @Override

    putEdge(N1, N1);
    assertThat(graph.outDegree(N1)).isEqualTo(2);
    putEdge(N2, N1);
    assertThat(graph.outDegree(N1)).isEqualTo(3);
  }

  // Stable order tests

  // Note: Stable order means that the ordering doesn't change between iterations and versions.
  // Ideally, the ordering in test should never be updated.
  @Test
  public void stableIncidentEdgeOrder_edges_returnsInStableOrder() {

 * @param <N> Node parameter type
 */
interface ArchetypeGraph<N> extends SuccessorsFunction<N>, PredecessorsFunction<N> {
  //
  // Graph-level accessors
  //

  /** Returns all nodes in this graph, in the order specified by {@link #nodeOrder()}. */
  Set<N> nodes();

  //
  // Graph properties
  //

  /**
   * Returns true if the edges in this graph are directed. Directed edges connect a {@link

                  protected Set<String> create(String[] elements) {
                    return new SafeTreeSet<>(asList(elements));
                  }

                  @Override
                  public List<String> order(List<String> insertionOrder) {
                    return new ArrayList<>(Sets.newTreeSet(insertionOrder));
                  }
                })
            .withFeatures(
                CollectionSize.ANY,

    }
    return tmp;
  }

  @Benchmark
  long parseUnsignedLong(int reps) {
    long tmp = 0;
    // Given that we make three calls per pass, we scale reps down in order
    // to do a comparable amount of work to other measurements.
    int scaledReps = reps / 3 + 1;
    for (int i = 0; i < scaledReps; i++) {
      int j = i & ARRAY_MASK;

   * perform better than its longhand equivalent, but should not perform worse.
   *
   * @since 12.0
   */
  HashCode hashInt(int input);

  /**
   * Shortcut for {@code newHasher().putLong(input).hash()}; returns the hash code for the given
   * {@code long} value, interpreted in little-endian byte order. The implementation <i>might</i>