```Python
with open("./somefile.txt") as f:
    contents = f.read()
    print(contents)
```

Internamente, `open("./somefile.txt")` crea un objeto llamado "Context Manager".

Cuando el bloque `with` termina, se asegura de cerrar el archivo, incluso si hubo excepciones.

		gr, err := objectAPI.GetObjectNInfo(ctx, bucket, zipPath, rs, nil, opts)
		if err != nil {
			writeErrorResponse(ctx, w, toAPIError(ctx, err), r.URL)
			return
		}
		defer gr.Close()
		rc, err = file.Open(gr)
		if err != nil {
			writeErrorResponse(ctx, w, toAPIError(ctx, err), r.URL)
			return
		}
	} else {
		rc = io.NopCloser(bytes.NewReader([]byte{}))
	}

	defer rc.Close()

				</component>
			</arg>
		</postConstruct>
	</component>
	<component name="osddHelper" class="org.codelibs.fess.helper.OsddHelper">
		<property name="osddPath">"/WEB-INF/orig/open-search/osdd.xml"</property>
		<property name="encoding">"UTF-8"</property>
	</component>
	<component name="suggestHelper" class="org.codelibs.fess.helper.SuggestHelper">
	</component>

 limitations under the License.
-->
Contributing to Apache Maven
======================

You have found a bug or you have an idea for a cool new feature? Contributing
code is a great way to give something back to the open source community. Before
you dig right into the code, there are a few guidelines that we need
contributors to follow so that we can have a chance of keeping on top of
things.

Você pode:

* <a href="https://github.com/tiangolo" class="external-link" target="_blank">Me siga no **GitHub**</a>.
    * Ver também outros projetos Open Source criados por mim que podem te ajudar.
    * Me seguir para saber quando um novo projeto Open Source for criado.
* <a href="https://x.com/tiangolo" class="external-link" target="_blank">Me siga no **X (Twitter)**</a>.

        new ByteSource() {
          @Override
          public InputStream openStream() throws IOException {
            if (counter[0]++ != 0) {
              throw new IllegalStateException("More than one source open");
            }
            return new FilterInputStream(source.openStream()) {
              @Override
              public void close() throws IOException {
                super.close();
                counter[0]--;

/*
 * Copyright (C) 2012 The Android Open Source Project
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,

/**
 * Manages reuse of HTTP and HTTP/2 connections for reduced network latency. HTTP requests that
 * share the same [Address] may share a [Connection]. This class implements the policy
 * of which connections to keep open for future use.
 *
 * @constructor Create a new connection pool with tuning parameters appropriate for a single-user
 * application. The tuning parameters in this pool are subject to change in future OkHttp releases.

{* ../../docs_src/custom_response/tutorial007.py hl[2,14] *}

#### Usando `StreamingResponse` con objetos similares a archivos

Si tienes un objeto similar a un archivo (por ejemplo, el objeto devuelto por `open()`), puedes crear una función generadora para iterar sobre ese objeto similar a un archivo.

De esa manera, no tienes que leerlo todo primero en memoria, y puedes pasar esa función generadora al `StreamingResponse`, y devolverlo.

				return nil, e
			}
			buf = bytes.NewBuffer(b)
		}

		return buf.Bytes(), nil
	}

	fmt.Println("{")

	hasWritten := false
	var r io.Reader
	var sz int64
	f, e := os.Open(downloadPath)
	if e != nil {
		return e
	}
	if st, e := f.Stat(); e == nil {
		sz = st.Size()
	}
	defer f.Close()
	r = f

	zr, e := zip.NewReader(r.(io.ReaderAt), sz)
	if e != nil {