* provided null elements.
   */
  public Joiner skipNulls() {
    return new Joiner(this) {
      @Override
      @SuppressWarnings("JoinIterableIterator") // suggests infinite recursion
      public String join(Iterable<?> parts) {
        return join(parts.iterator());
      }

      @Override

                    ((SmbComTransactionResponse) resp).nextElement();
                }
            }

            /* Verification fails (w/ W2K3 server at least) if status is not 0. This
             * suggests MS doesn't compute the signature (correctly) for error responses
             * (perhaps for DOS reasons).
             */
            if (digest != null && resp.errorCode == 0) {
                digest.verify(BUF, 4, resp);

* 너그러운 마음이 든다면, 문제 설명만을 기반으로 직접 **예제를 만들어**볼 수도 있습니다. 다만 이는 시간이 많이 걸릴 수 있으므로, 먼저 문제를 명확히 해달라고 요청하는 것이 더 나을 수 있다는 점을 기억하세요.

### 해결책 제안하기 { #suggest-solutions }

* 질문을 충분히 이해한 후에는 가능한 **답변**을 제공할 수 있습니다.

* 많은 경우, 질문자의 **근본적인 문제나 사용 사례**를 이해하는 것이 더 좋습니다. 그들이 시도하는 방법보다 더 나은 해결책이 있을 수 있기 때문입니다.

### 종료 요청하기 { #ask-to-close }

        setConfig(100, 50);
        testableFilter.setCpuPercent((short) 60);

        String[] apiPaths = { "/api/v1/search", "/api/v1/documents", "/api/v2/suggest" };
        for (String path : apiPaths) {
            resetMocks();
            mockRequest.setRequestURI(path);
            testableFilter.doFilter(mockRequest, mockResponse, mockFilterChain);

    return x > 0 & (x & (x - 1)) == 0;
  }

  /**
   * Returns 1 if {@code x < y} as unsigned longs, and 0 otherwise. Assumes that x - y fits into a
   * signed long. The implementation is branch-free, and benchmarks suggest it is measurably faster
   * than the straightforward ternary expression.
   */
  @VisibleForTesting
  static int lessThanBranchFree(long x, long y) {

                searchLogList.forEach(this::writeSearchLogEvent);
            }
            // insert search log
            storeSearchLogList(searchLogList);
            // update suggest index
            if (fessConfig.isSuggestSearchLog()) {
                final SuggestHelper suggestHelper = ComponentUtil.getSuggestHelper();
                suggestHelper.indexFromSearchLog(searchLogList);
            }

* 你可以请他们提供一个[可最小复现的示例](https://stackoverflow.com/help/minimal-reproducible-example)，你可以**复制粘贴**并在本地运行，看到与他们相同的错误或行为，或者更好地理解他们的用例。

* 如果你非常热心，你也可以尝试仅根据问题描述自己**构造一个示例**。不过要记住，这可能会花很多时间，通常先请他们澄清问题会更好。

### 提出解决方案 { #suggest-solutions }

* 在能够理解问题之后，你可以给出一个可能的**答案**。

* 很多情况下，更好的是去理解他们**底层的问题或场景**，因为可能存在比他们尝试的方法更好的解决方式。

### 请求关闭问题 { #ask-to-close }

如果他们回复了，很有可能你已经解决了他们的问题，恭喜，**你是英雄**！🦸

* 现在，如果问题已解决，你可以请他们：

      return Arrays.copyOfRange(array, start, end);
    }

    @GwtIncompatible @J2ktIncompatible private static final long serialVersionUID = 0;
  }

  /**
   * This is adapted from the regex suggested by {@link Double#valueOf(String)} for prevalidating
   * inputs. All valid inputs must pass this regex, but it's semantically fine if not all inputs

    String leading = ",a,b,c";
    Iterable<String> letters = Splitter.onPattern(",").split(leading);
    assertThat(letters).containsExactly("", "a", "b", "c").inOrder();
  }

  // TODO(kevinb): the name of this method suggests it might not actually be testing what it
  // intends to be testing?
  @GwtIncompatible // Splitter.onPattern
  public void testPatternSplitWithMultipleLetters() {
    Iterable<String> testPatterningMotto =

    return x > 0 & (x & (x - 1)) == 0;
  }

  /**
   * Returns 1 if {@code x < y} as unsigned integers, and 0 otherwise. Assumes that x - y fits into
   * a signed int. The implementation is branch-free, and benchmarks suggest it is measurably (if
   * narrowly) faster than the straightforward ternary expression.
   */
  @VisibleForTesting
  static int lessThanBranchFree(int x, int y) {