if (tmp == null) {
        return emptySet(comparator());
      }
      fromElement = tmp;
    }
    return tailSet(fromElement);
  }

  public static <E> Builder<E> orderedBy(Comparator<E> comparator) {
    return new Builder<E>(comparator);
  }

  public static <E extends Comparable<?>> Builder<E> reverseOrder() {
    return new Builder<E>(Ordering.natural().reverse());
  }

    }
    map.put(key, value);
  }

  public static <K extends Comparable<?>, V> Builder<K, V> naturalOrder() {
    return new Builder<K, V>(Ordering.natural());
  }

  public static <K, V> Builder<K, V> orderedBy(Comparator<K> comparator) {
    return new Builder<K, V>(comparator);
  }

  public static <K extends Comparable<?>, V> Builder<K, V> reverseOrder() {
    return new Builder<K, V>(Ordering.natural().reverse());
  }

   *
   * @throws NullPointerException if {@code comparator} is null
   */
  public static <K, V> Builder<K, V> orderedBy(Comparator<K> comparator) {
    return new Builder<>(comparator);
  }

  /**
   * Returns a builder that creates immutable sorted maps whose keys are ordered by the reverse of
   * their natural ordering.
   */
  public static <K extends Comparable<?>, V> Builder<K, V> reverseOrder() {

    return set;
  }

  /**
   * Creates a <i>mutable</i>, empty {@code TreeSet} instance with the given comparator.
   *
   * <p><b>Note:</b> if mutability is not required, use {@code
   * ImmutableSortedSet.orderedBy(comparator).build()} instead.
   *
   * <p><b>Note:</b> this method is now unnecessary and should be treated as deprecated. Instead,
   * use the {@code TreeSet} constructor directly, taking advantage of <a

  }

  /**
   * Creates a <i>mutable</i>, empty {@code TreeMap} instance using the given comparator.
   *
   * <p><b>Note:</b> if mutability is not required, use {@code
   * ImmutableSortedMap.orderedBy(comparator).build()} instead.
   *
   * <p><b>Note:</b> this method is now unnecessary and should be treated as deprecated. Instead,
   * use the {@code TreeMap} constructor directly, taking advantage of <a

  }

  /**
   * Creates a <i>mutable</i>, empty {@code TreeMap} instance using the given comparator.
   *
   * <p><b>Note:</b> if mutability is not required, use {@code
   * ImmutableSortedMap.orderedBy(comparator).build()} instead.
   *
   * <p><b>Note:</b> this method is now unnecessary and should be treated as deprecated. Instead,
   * use the {@code TreeMap} constructor directly, taking advantage of <a

    /**
     * Returns an immutable list of project remote repositories (directly specified or inherited).
     * The repositories are ordered by declaration order, with inherited repositories appearing
     * after directly specified ones.
     *
     * @param project the project
     * @return ordered list of remote repositories
     */
    @Nonnull
    List<RemoteRepository> getRemoteProjectRepositories(@Nonnull Project project);

    }

    @Test
    void testSameWeightOrdering() {
        // Test that projects with the same weight are ordered by project ID
        // Projects B and C both have weight 2, so they should be ordered by project ID
        List<MavenProject> projects = Arrays.asList(
                ProjectDependencyGraphStub.C, // weight=2, ID contains "C"

pkg bytes, method (*Buffer) AvailableBuffer() []uint8 #53685
pkg bytes, method (*Buffer) Available() int #53685
pkg cmp, func Compare[$0 Ordered]($0, $0) int #59488
pkg cmp, func Less[$0 Ordered]($0, $0) bool #59488
pkg cmp, type Ordered interface {} #59488
pkg context, func AfterFunc(Context, func()) func() bool #57928
pkg context, func WithDeadlineCause(Context, time.Time, error) (Context, CancelFunc) #56661

 *
 * <p>Projects are then sorted by weight in descending order, ensuring that
 * projects with longer dependency chains are built first. When projects have
 * the same weight, they are ordered by project ID for deterministic results.
 *
 * <p><b>Example:</b>
 * <p>Consider projects with dependencies: A → B → D, A → C → D
 * <ul>
 * <li>Project D: weight = 1 (no downstream dependencies)</li>