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Results 11 - 16 of 16 for log1p (0.03 seconds)

  1. android/guava-tests/benchmark/com/google/common/math/LongMathRoundingBenchmark.java

          int j = i & ARRAY_MASK;
          tmp += LongMath.log2(positive[j], mode);
        }
        return tmp;
      }
    
      @Benchmark
      int log10(int reps) {
        int tmp = 0;
        for (int i = 0; i < reps; i++) {
          int j = i & ARRAY_MASK;
          tmp += LongMath.log10(positive[j], mode);
        }
        return tmp;
      }
    
      @Benchmark
      int sqrt(int reps) {
        int tmp = 0;
        for (int i = 0; i < reps; i++) {
    Created: Fri Apr 03 12:43:13 GMT 2026
    - Last Modified: Thu Dec 19 18:03:30 GMT 2024
    - 2.6K bytes
    - Click Count (0)
  2. guava-tests/benchmark/com/google/common/math/IntMathRoundingBenchmark.java

          int j = i & ARRAY_MASK;
          tmp += IntMath.log2(positive[j], mode);
        }
        return tmp;
      }
    
      @Benchmark
      int log10(int reps) {
        int tmp = 0;
        for (int i = 0; i < reps; i++) {
          int j = i & ARRAY_MASK;
          tmp += IntMath.log10(positive[j], mode);
        }
        return tmp;
      }
    
      @Benchmark
      int sqrt(int reps) {
        int tmp = 0;
        for (int i = 0; i < reps; i++) {
    Created: Fri Apr 03 12:43:13 GMT 2026
    - Last Modified: Thu Dec 19 18:03:30 GMT 2024
    - 2.6K bytes
    - Click Count (0)
  3. android/guava/src/com/google/common/math/IntMath.java

         * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
         * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
         */
        int y = maxLog10ForLeadingZeros[Integer.numberOfLeadingZeros(x)];
        /*
         * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
    Created: Fri Apr 03 12:43:13 GMT 2026
    - Last Modified: Thu Jan 29 22:14:05 GMT 2026
    - 26.1K bytes
    - Click Count (0)
  4. android/guava/src/com/google/common/math/LongMath.java

         * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
         * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
         */
        int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)];
        /*
         * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
    Created: Fri Apr 03 12:43:13 GMT 2026
    - Last Modified: Mon Mar 09 23:01:02 GMT 2026
    - 46.8K bytes
    - Click Count (0)
  5. RELEASE.md

            `tf.math.greater`, `tf.math.greater_equal`, `tf.math.igamma`,
            `tf.math.igammac`, `tf.math.invert_permutation`, `tf.math.less`,
            `tf.math.less_equal`, `tf.math.lgamma`, `tf.math.log`, `tf.math.log1p`,
            `tf.math.logical_and`, `tf.math.logical_not`, `tf.math.logical_or`,
            `tf.math.maximum`, `tf.math.minimum`, `tf.math.not_equal`,
            `tf.math.polygamma`, `tf.math.reciprocal`, `tf.math.rint`,
    Created: Tue Apr 07 12:39:13 GMT 2026
    - Last Modified: Mon Mar 30 18:31:38 GMT 2026
    - 746.5K bytes
    - Click Count (3)
  6. api/go1.txt

    pkg math, func Jn(int, float64) float64
    pkg math, func Ldexp(float64, int) float64
    pkg math, func Lgamma(float64) (float64, int)
    pkg math, func Log(float64) float64
    pkg math, func Log10(float64) float64
    pkg math, func Log1p(float64) float64
    pkg math, func Log2(float64) float64
    pkg math, func Logb(float64) float64
    pkg math, func Max(float64, float64) float64
    pkg math, func Min(float64, float64) float64
    Created: Tue Apr 07 11:13:11 GMT 2026
    - Last Modified: Wed Aug 14 18:58:28 GMT 2013
    - 1.7M bytes
    - Click Count (0)
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