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Results 11 - 16 of 16 for log1p (0.09 sec)

  1. guava-tests/benchmark/com/google/common/math/IntMathRoundingBenchmark.java

          int j = i & ARRAY_MASK;
          tmp += IntMath.log2(positive[j], mode);
        }
        return tmp;
      }
    
      @Benchmark
      int log10(int reps) {
        int tmp = 0;
        for (int i = 0; i < reps; i++) {
          int j = i & ARRAY_MASK;
          tmp += IntMath.log10(positive[j], mode);
        }
        return tmp;
      }
    
      @Benchmark
      int sqrt(int reps) {
        int tmp = 0;
        for (int i = 0; i < reps; i++) {
    Registered: Fri Nov 01 12:43:10 UTC 2024
    - Last Modified: Mon Dec 04 17:37:03 UTC 2017
    - 2.6K bytes
    - Viewed (0)
  2. guava/src/com/google/common/math/BigIntegerMath.java

       *     is not a power of ten
       */
      @GwtIncompatible // TODO
      @SuppressWarnings("fallthrough")
      public static int log10(BigInteger x, RoundingMode mode) {
        checkPositive("x", x);
        if (fitsInLong(x)) {
          return LongMath.log10(x.longValue(), mode);
        }
    
        int approxLog10 = (int) (log2(x, FLOOR) * LN_2 / LN_10);
        BigInteger approxPow = BigInteger.TEN.pow(approxLog10);
    Registered: Fri Nov 01 12:43:10 UTC 2024
    - Last Modified: Wed Oct 16 17:21:56 UTC 2024
    - 18.8K bytes
    - Viewed (0)
  3. android/guava/src/com/google/common/math/LongMath.java

         * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
         * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
         */
        int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)];
        /*
         * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
    Registered: Fri Nov 01 12:43:10 UTC 2024
    - Last Modified: Wed Oct 09 16:39:37 UTC 2024
    - 45.2K bytes
    - Viewed (0)
  4. guava/src/com/google/common/math/LongMath.java

         * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
         * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
         */
        int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)];
        /*
         * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
    Registered: Fri Nov 01 12:43:10 UTC 2024
    - Last Modified: Wed Oct 09 16:39:37 UTC 2024
    - 45.2K bytes
    - Viewed (0)
  5. RELEASE.md

            `tf.math.greater`, `tf.math.greater_equal`, `tf.math.igamma`,
            `tf.math.igammac`, `tf.math.invert_permutation`, `tf.math.less`,
            `tf.math.less_equal`, `tf.math.lgamma`, `tf.math.log`, `tf.math.log1p`,
            `tf.math.logical_and`, `tf.math.logical_not`, `tf.math.logical_or`,
            `tf.math.maximum`, `tf.math.minimum`, `tf.math.not_equal`,
            `tf.math.polygamma`, `tf.math.reciprocal`, `tf.math.rint`,
    Registered: Tue Nov 05 12:39:12 UTC 2024
    - Last Modified: Tue Oct 22 14:33:53 UTC 2024
    - 735.3K bytes
    - Viewed (0)
  6. api/go1.txt

    pkg math, func Jn(int, float64) float64
    pkg math, func Ldexp(float64, int) float64
    pkg math, func Lgamma(float64) (float64, int)
    pkg math, func Log(float64) float64
    pkg math, func Log10(float64) float64
    pkg math, func Log1p(float64) float64
    pkg math, func Log2(float64) float64
    pkg math, func Logb(float64) float64
    pkg math, func Max(float64, float64) float64
    pkg math, func Min(float64, float64) float64
    Registered: Tue Nov 05 11:13:11 UTC 2024
    - Last Modified: Wed Aug 14 18:58:28 UTC 2013
    - 1.7M bytes
    - Viewed (0)
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