}
      return BigInteger.valueOf(result);
    }

    /*
     * We want each multiplication to have both sides with approximately the same number of digits.
     * Currently, we just divide the range in half.
     */
    int mid = (n1 + n2) >>> 1;
    return oldSlowFactorial(n1, mid).multiply(oldSlowFactorial(mid, n2));
  }

  @Benchmark
  int slowFactorial(int reps) {
    int tmp = 0;

  static <R, C, V> RegularImmutableTable<R, C, V> forOrderedComponents(
      ImmutableList<Cell<R, C, V>> cellList,
      ImmutableSet<R> rowSpace,
      ImmutableSet<C> columnSpace) {
    // use a dense table if more than half of the cells have values
    // TODO(gak): tune this condition based on empirical evidence
    return (cellList.size() > (((long) rowSpace.size() * columnSpace.size()) / 2))

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  }

  private static long random() {
    return randomSource.nextLong();
  }

  // A random value that cannot be 0 and that is unsigned-less-than or equal
  // to the given dividend, so that we don't have half of our divisions being
  // trivial because the divisor is bigger than the dividend.
  // Using remainder here does not give us a uniform distribution but it should
  // not have a big impact on the measurement.

        return (logX2Floor < 2 * logFloor + 1) ? logFloor : logFloor + 1;
    }
    throw new AssertionError();
  }

  /*
   * The maximum number of bits in a square root for which we'll precompute an explicit half power
   * of two. This can be any value, but higher values incur more class load time and linearly
   * increasing memory consumption.
   */
  @VisibleForTesting static final int SQRT2_PRECOMPUTE_THRESHOLD = 256;

	// runtime stack of go routines will be listed with 2 blank spaces between each of them, so split on "\n\n" .
	for g := range strings.SplitSeq(string(buf), "\n\n") {
		// Again split on a new line, the first line of the second half contains the info about the go routine.
		sl := strings.SplitN(g, "\n", 2)
		if len(sl) != 2 {
			continue
		}
		stack := strings.TrimSpace(sl[1])
		// ignore the testing go routine.

      // return condition1 || condition2;
      if (nodeU().equals(other.nodeU())) { // check condition1
        // Here's the tricky bit. We don't have to explicitly check for condition2 in this case.
        // Why? The second half of condition2 requires that nodeV equals other.nodeU.
        // We already know that nodeU equals other.nodeU. Combined with the earlier statement,

     * @param failureThreshold number of failures before opening
     * @param successThreshold number of successes in half-open before closing
     * @param resetTimeoutMillis time to wait before attempting reset (ms)
     * @param halfOpenMaxAttempts max attempts in half-open state
     */

      // return condition1 || condition2;
      if (nodeU().equals(other.nodeU())) { // check condition1
        // Here's the tricky bit. We don't have to explicitly check for condition2 in this case.
        // Why? The second half of condition2 requires that nodeV equals other.nodeU.
        // We already know that nodeU equals other.nodeU. Combined with the earlier statement,

    // So we can ignore the bottom 11, except for rounding. We can unsigned-shift right 1, aka
    // unsigned-divide by 2, and convert that. Then we'll get exactly half of the desired double
    // value. But in the specific case where the bottom two bits of the original number are 01, we
    // want to replace that with 1 in the shifted value for correct rounding.