return fromLongBits(value * checkNotNull(val).value);
  }

  /**
   * Returns the result of dividing this by {@code val}.
   *
   * @since 14.0
   */
  public UnsignedLong dividedBy(UnsignedLong val) {
    return fromLongBits(UnsignedLongs.divide(value, checkNotNull(val).value));
  }

  /**
   * Returns this modulo {@code val}.
   *
   * @since 14.0
   */

    return fromLongBits(value * checkNotNull(val).value);
  }

  /**
   * Returns the result of dividing this by {@code val}.
   *
   * @since 14.0
   */
  public UnsignedLong dividedBy(UnsignedLong val) {
    return fromLongBits(UnsignedLongs.divide(value, checkNotNull(val).value));
  }

  /**
   * Returns this modulo {@code val}.
   *
   * @since 14.0
   */

        } else if (size.divide(ONE_GB_BI).compareTo(BigInteger.ZERO) > 0) {
            displaySize = new BigDecimal(size.divide(ONE_MB_BI)).divide(BigDecimal.valueOf(1000)) + "GB";
        } else if (size.divide(ONE_MB_BI).compareTo(BigInteger.ZERO) > 0) {
            displaySize = new BigDecimal(size.divide(ONE_KB_BI)).divide(BigDecimal.valueOf(1000)) + "MB";

    a >>= aTwos; // divide out all 2s
    int bTwos = Long.numberOfTrailingZeros(b);
    b >>= bTwos; // divide out all 2s
    while (a != b) { // both a, b are odd
      // The key to the binary GCD algorithm is as follows:
      // Both a and b are odd. Assume a > b; then gcd(a - b, b) = gcd(a, b).
      // But in gcd(a - b, b), a - b is even and b is odd, so we can divide out powers of two.

    a >>= aTwos; // divide out all 2s
    int bTwos = Long.numberOfTrailingZeros(b);
    b >>= bTwos; // divide out all 2s
    while (a != b) { // both a, b are odd
      // The key to the binary GCD algorithm is as follows:
      // Both a and b are odd. Assume a > b; then gcd(a - b, b) = gcd(a, b).
      // But in gcd(a - b, b), a - b is even and b is odd, so we can divide out powers of two.

    return fromIntBits(value * checkNotNull(val).value);
  }

  /**
   * Returns the result of dividing this by {@code val}.
   *
   * @throws ArithmeticException if {@code val} is zero
   * @since 14.0
   */
  public UnsignedInteger dividedBy(UnsignedInteger val) {
    return fromIntBits(UnsignedInts.divide(value, checkNotNull(val).value));
  }

  /**
   * Returns this mod {@code val}.
   *

    return fromIntBits(value * checkNotNull(val).value);
  }

  /**
   * Returns the result of dividing this by {@code val}.
   *
   * @throws ArithmeticException if {@code val} is zero
   * @since 14.0
   */
  public UnsignedInteger dividedBy(UnsignedInteger val) {
    return fromIntBits(UnsignedInts.divide(value, checkNotNull(val).value));
  }

  /**
   * Returns this mod {@code val}.
   *

 x     y     x / y     x % y
 5     3       1         2
-5     3      -1        -2
 5    -3      -1         2
-5    -3       1        -2
</pre>

<p>
The one exception to this rule is that if the dividend <code>x</code> is
the most negative value for the int type of <code>x</code>, the quotient
<code>q = x / -1</code> is equal to <code>x</code> (and <code>r = 0</code>)

   * @param iterable the iterable to return a partitioned view of
   * @param size the desired size of each partition (the last may be smaller)
   * @return an iterable of unmodifiable lists containing the elements of {@code iterable} divided
   *     into partitions
   * @throws IllegalArgumentException if {@code size} is nonpositive
   */
  public static <T extends @Nullable Object> Iterable<List<T>> partition(

    }

    val expectedBucketSize = list.sumOf(toIntFunction) / expectedBucketNumber

    if (expectedBucketSize == 0) {
        // The elements in the list are so small that they can't even be divided into {expectedBucketNumber}.
        // For example, how do you split [0,0,0,0,0] into 3 buckets?
        // In this case, we simply put the elements into these buckets evenly.