*
   * <p>If the graph is directed, the resultant edge will be directed; otherwise, it will be
   * undirected.
   *
   * <p>If this graph is directed, {@code endpoints} must be ordered.
   *
   * <p>Values do not have to be unique. However, values must be non-null.
   *
   * <p>If either or both endpoints are not already present in this graph, this method will silently

    } else {
      return false;
    }
    return comparator.equals(comparator2);
  }

  @SuppressWarnings("unchecked")
  // if sortedSet.comparator() is null, the set must be naturally ordered
  public static <E extends @Nullable Object> Comparator<? super E> comparator(
      SortedSet<E> sortedSet) {
    Comparator<? super E> result = sortedSet.comparator();
    if (result == null) {

   * equally valid implementation for an unordered container is to throw an exception. The chosen
   * implementation, however, has the advantage of working for insertion-ordered containers, as
   * well.
   */
  @Override
  public List<Integer> order(List<Integer> insertionOrder) {
    return insertionOrder;
  }

    assertThat(min(0x5a4316b8c153ac4dL, 8L, 100L, 0L, 0x6cf78a4b139a4e2aL, 0xff1a618b7f65ea12L))
        .isEqualTo(0L);
  }

  public void testLexicographicalComparator() {
    List<long[]> ordered =
        Arrays.asList(
            new long[] {},
            new long[] {LEAST},
            new long[] {LEAST, LEAST},
            new long[] {LEAST, 1L},
            new long[] {1L},

    } else {
      return false;
    }
    return comparator.equals(comparator2);
  }

  @SuppressWarnings("unchecked")
  // if sortedSet.comparator() is null, the set must be naturally ordered
  public static <E extends @Nullable Object> Comparator<? super E> comparator(
      SortedSet<E> sortedSet) {
    Comparator<? super E> result = sortedSet.comparator();
    if (result == null) {

import java.util.Set;
import java.util.SortedMap;
import java.util.SortedSet;
import java.util.TreeMap;
import org.jspecify.annotations.Nullable;

/**
 * Implementation of {@code Table} whose row keys and column keys are ordered by their natural
 * ordering or by supplied comparators. When constructing a {@code TreeBasedTable}, you may provide
 * comparators for the row keys and the column keys, or you may use natural ordering for both.
 *

  public void testForEachKnownOrder() {
    List<E> elements = new ArrayList<>();
    collection.forEach(elements::add);
    List<E> expected = Helpers.copyToList(getOrderedElements());
    assertEquals("Different ordered iteration", expected, elements);
  }

    Helpers.testComparator(comparator, ordered);
    assertThat(SerializableTester.reserialize(comparator)).isSameInstanceAs(comparator);

    // The Java implementation.
    Comparator<byte[]> javaImpl = UnsignedBytes.lexicographicalComparatorJavaImpl();
    Helpers.testComparator(javaImpl, ordered);
    assertThat(SerializableTester.reserialize(javaImpl)).isSameInstanceAs(javaImpl);
  }

     * endpoints}) if one is not already present.
     *
     * <p>If this graph is directed, {@code endpoints} must be ordered and the added edge will be
     * directed; if it is undirected, the added edge will be undirected.
     *
     * <p>If this graph is directed, {@code endpoints} must be ordered.
     *
     * <p>If either or both endpoints are not already present in this graph, this method will

  /**
   * Returns a builder that creates immutable sorted sets whose elements are ordered by the reverse
   * of their natural ordering.
   */
  public static <E extends Comparable<?>> Builder<E> reverseOrder() {
    return new Builder<>(Collections.reverseOrder());
  }

  /**
   * Returns a builder that creates immutable sorted sets whose elements are ordered by their