Autoriza la aplicación de la misma manera que antes.

Usando las credenciales:

Usuario: `johndoe`
Contraseña: `secret`

/// check | Revisa

Observa que en ninguna parte del código está la contraseña en texto claro "`secret`", solo tenemos la versión con hash.

///

<img src="/img/tutorial/security/image08.png">

Llama al endpoint `/users/me/`, obtendrás el response como:

`user_in`은 Pydantic 모델 클래스인 `UserIn`입니다.

Pydantic 모델은 모델 데이터를 포함한 `dict`를 반환하는 `.model_dump()` 메서드를 제공합니다.

따라서, 다음과 같이 Pydantic 객체 `user_in`을 생성할 수 있습니다:

```Python
user_in = UserIn(username="john", password="secret", email="******@****.***")
```

그 다음, 다음과 같이 호출합니다:

```Python
user_dict = user_in.model_dump()
```

이제 변수 `user_dict`에 데이터가 포함된 `dict`를 가지게 됩니다(이는 Pydantic 모델 객체가 아닌 `dict`입니다).

그리고 다음과 같이 호출하면:

Em muitos casos, sua aplicação FastAPI será maior, e você provavelmente usará tags para separar diferentes grupos de *operações de rota*.

Por exemplo, você poderia ter uma seção para **items** e outra seção para **users**, e elas poderiam ser separadas por tags:

{* ../../docs_src/generate_clients/tutorial002_py310.py hl[21,26,34] *}

Autorisez l'application de la même manière qu'auparavant.

En utilisant les identifiants :

Nom d'utilisateur : `johndoe`
Mot de passe : `secret`

/// check | Vérifications

Remarquez qu'à aucun endroit du code le mot de passe en clair « secret » n'apparaît, nous n'avons que la version hachée.

///

<img src="/img/tutorial/security/image08.png">

/**
 * API access to the <a href="https://api.slack.com/apps">Slack API</a> as an application. One
 * instance of this class may operate without a user, or on behalf of many users. Use the Slack API
 * dashboard to create a client ID and secret for this application.
 *
 * <p>You must configure your Slack API OAuth and Permissions page with a localhost URL like {@code
 * http://localhost:53203/oauth/}, passing the same port to this class’ constructor.
 */

Example: Limit a MinIO cluster to accept at max 1600 simultaneous S3 API requests across all nodes of the cluster.

```sh
export MINIO_API_REQUESTS_MAX=1600
export MINIO_ROOT_USER=your-access-key
export MINIO_ROOT_PASSWORD=your-secret-key
minio server http://server{1...8}/mnt/hdd{1...16}
```

or

```sh
mc admin config set myminio/ api requests_max=1600
mc admin service restart myminio/
```

 *   // If this is preemptive auth, use a preemptive credential.
 *   if (challenge.scheme().equalsIgnoreCase("OkHttp-Preemptive")) {
 *     return response.request().newBuilder()
 *         .header("Proxy-Authorization", "secret")
 *         .build();
 *   }
 * }
 * return null; // Didn't find a preemptive auth scheme.
 * ```
 *
 * ## Reactive Authentication
 *

    // Patterns for sensitive data - compiled once and cached
    private static final Pattern PASSWORD_PATTERN = Pattern.compile(
            "(?i)(password|passwd|pwd|secret|token|key|credential|auth)([\"']?\\s*[:=]\\s*[\"']?)([^\"',\\s]+)", Pattern.CASE_INSENSITIVE);

    private static final Pattern IP_PATTERN = Pattern.compile("\\b(?:[0-9]{1,3}\\.){3}[0-9]{1,3}\\b");

Пройдите авторизацию так же, как делали раньше.

Используя учетные данные пользователя:

Username: `johndoe`
Password: `secret`

/// check | Проверка

Обратите внимание, что нигде в коде не используется открытый текст пароля "`secret`", мы используем только его хэшированную версию.

///

<img src="/img/tutorial/security/image08.png">

#include "tensorflow/core/framework/tensor_shape.h"
#include "tensorflow/core/framework/types.pb.h"
#include "tensorflow/core/lib/llvm_rtti/llvm_rtti.h"
#include "tensorflow/core/platform/errors.h"
#include "tensorflow/core/platform/strcat.h"
#include "tensorflow/core/platform/types.h"

using tensorflow::dyn_cast;
using tensorflow::string;
using tensorflow::gtl::ArraySlice;

namespace tensorflow {
namespace tracing {
namespace graph {