if (occurrences == 0) {
      return count(element);
    }
    checkArgument(occurrences > 0, "occurrences cannot be negative: %s", occurrences);
    int entryIndex = backingMap.indexOf(element);
    if (entryIndex == -1) {
      backingMap.put(element, occurrences);
      size += occurrences;
      return 0;
    }
    int oldCount = backingMap.getValue(entryIndex);

    //     ends up at a[d], which in turn ends up at a[2d], and so on until we get back to a[0].
    //     (All indices taken mod n.) If d and n are mutually prime, all elements will have been
    //     moved at that point. Otherwise, we can rotate the cycle a[1], a[1 + d], a[1 + 2d], etc,
    //     then a[2] etc, and so on until we have rotated all elements. There are gcd(d, n) cycles

  }

  /**
   * Reverses the elements of {@code array}. This is equivalent to {@code
   * Collections.reverse(Booleans.asList(array))}, but is likely to be more efficient.
   *
   * @since 23.1
   */
  public static void reverse(boolean[] array) {
    checkNotNull(array);
    reverse(array, 0, array.length);
  }

  /**

  /** Test an empty collection. */
  ZERO(0),
  /** Test a one-element collection. */
  ONE(1),
  /** Test a three-element collection. */
  SEVERAL(3),
  /*
   * TODO: add VERY_LARGE, noting that we currently assume that the fourth
   * sample element is not in any collection
   */

  ANY(ZERO, ONE, SEVERAL);

  private final Set<Feature<? super Collection>> implied;

  /** Test an empty collection. */
  ZERO(0),
  /** Test a one-element collection. */
  ONE(1),
  /** Test a three-element collection. */
  SEVERAL(3),
  /*
   * TODO: add VERY_LARGE, noting that we currently assume that the fourth
   * sample element is not in any collection
   */

  ANY(ZERO, ONE, SEVERAL);

  private final Set<Feature<? super Collection>> implied;

        List<Element> valueTitles = new ArrayList<Element>();
        for (int i = 1; i < header.size(); i++) {
            Element element = header.get(i);
            Element override = findChild(element, "overrides");
            if (override != null) {
                element.removeChild(override);
                inheritedValueTitleMapping.put(override.getTextContent(), element);
            }
            Node firstChild = element.getFirstChild();

     * For example, if this type is {@link #MODULES}, then the option is {@code "--module-path"}
     * followed by the specified path elements.
     * The paths are not quoted.
     *
     * @param paths the path to format as a tool option
     * @return the option associated to this path type followed by the given path elements,

   * <i>should</i> hold {@code expectedSize} elements without growth.
   *
   * @param expectedSize the number of elements you expect to add to the returned set
   * @return a new, empty {@code ObjectCountHashMap} with enough capacity to hold {@code
   *     expectedSize} elements without resizing
   * @throws IllegalArgumentException if {@code expectedSize} is negative
   */

    collection = getSubjectGenerator().create(arrayAndDuplicate.elements);
    E duplicate = arrayAndDuplicate.duplicate;

    int firstIndex = getList().indexOf(duplicate);
    int initialSize = getList().size();
    assertTrue("remove(present) should return true", getList().remove(duplicate));
    assertTrue(
        "After remove(duplicate), a list should still contain the duplicate element",
        getList().contains(duplicate));
    assertFalse(

  boolean isPartialView() {
    return false;
  }

  @Override
  public int count(@Nullable Object element) {
    @Nullable ImmutableEntry<?>[] hashTable = this.hashTable;
    if (element == null || hashTable.length == 0) {
      return 0;
    }
    int hash = smearedHash(element);
    int mask = hashTable.length - 1;
    for (ImmutableEntry<?> entry = hashTable[hash & mask];
        entry != null;