throw new GradleException("Must run in online mode in order to submit the dependency graph to the SCA service");
        }

        final DependencySet runtimeDependencies = runtimeConfiguration.getAllDependencies();
        final Set<String> packages = new HashSet<>();
        final Set<String> nodes = new HashSet<>();
        final Set<String> nodeIds = new HashSet<>();

import org.apache.maven.model.Parent;
import org.apache.maven.model.Plugin;
import org.apache.maven.model.PluginExecution;
import org.apache.maven.model.PluginManagement;
import org.apache.maven.model.Profile;
import org.apache.maven.model.ReportPlugin;
import org.apache.maven.model.Reporting;
import org.apache.maven.model.Repository;
import org.apache.maven.model.Resource;
import org.apache.maven.model.building.ModelBuildingRequest;

**Güncelleme** için tüm değerleri optional olan modeller ile **oluşturma** için zorunlu değerlere sahip modelleri ayırmak için, [Extra Models](extra-models.md) bölümünde anlatılan fikirleri kullanabilirsiniz.

import org.apache.maven.lifecycle.DefaultLifecycles;
import org.apache.maven.lifecycle.LifecycleExecutor;
import org.apache.maven.lifecycle.MavenExecutionPlan;
import org.apache.maven.model.Plugin;
import org.apache.maven.model.PluginExecution;
import org.apache.maven.plugin.MojoExecution;

/**
 * A stub implementation that assumes an empty lifecycle to bypass interaction with the plugin manager and to avoid

///

## Embed a single body parameter { #embed-a-single-body-parameter }

Let's say you only have a single `item` body parameter from a Pydantic model `Item`.

By default, **FastAPI** will then expect its body directly.

But if you want it to expect a JSON with a key `item` and inside of it the model contents, as it does when you declare extra body parameters, you can use the special `Body` parameter `embed`:

```Python

---> 100%
```

</div>

## Создание приложения с единственной моделью { #create-the-app-with-a-single-model }

Сначала мы создадим самую простую первую версию приложения с одной моделью **SQLModel**.

Позже мы улучшим его, повысив безопасность и универсальность, добавив **несколько моделей**. 🤓

### Создание моделей { #create-models }

Импортируйте `SQLModel` и создайте модель базы данных:

		uaAppend(" CPU ", fmt.Sprintf("(total_cpus:%d, total_cores:%d; vendor:%s; family:%s; model:%s; stepping:%d; model_name:%s)",
			len(cpuMap), len(coreMap), cpu.VendorID, cpu.Family, cpu.Model, cpu.Stepping, cpu.ModelName))
	}
	uaAppend(")", "")

	return strings.Join(userAgentParts, "")
}

func downloadReleaseURL(u *url.URL, timeout time.Duration, mode string) (content string, err error) {

				})
			}
		}
	})

	var models []User
	if err := DB.Where("name in (?)", []string{"find"}).Find(&models).Error; err != nil || len(models) != 3 {
		t.Errorf("errors happened when query find with in clause: %v, length: %v", err, len(models))
	} else {
		for idx, user := range users {
			t.Run("FindWithInClause#"+strconv.Itoa(idx+1), func(t *testing.T) {
				CheckUser(t, models[idx], user)
			})
		}
	}

     * @throws NullPointerException if name is null
     */
    @Nullable
    String attribute(@Nonnull String name);

    /**
     * Returns an immutable list of all child nodes.
     *
     * @return list of child nodes, never {@code null}
     */
    @Nonnull
    List<XmlNode> children();

    /**
     * Returns the first child node with the specified name.
     *

---> 100%
```

</div>

## Crear la App con un Solo Modelo { #create-the-app-with-a-single-model }

Primero crearemos la versión más simple de la aplicación con un solo modelo de **SQLModel**.

Más adelante la mejoraremos aumentando la seguridad y versatilidad con **múltiples modelos** a continuación. 🤓

### Crear Modelos { #create-models }

Importa `SQLModel` y crea un modelo de base de datos: