while (true) {
            try {
              e = q.poll(deadline - System.nanoTime(), NANOSECONDS);
              break;
            } catch (InterruptedException ex) {
              interrupted = true; // note interruption and retry
            }
          }
          if (e == null) {
            break; // we already waited enough, and there are no more elements in sight

    val call = client.newCall(request)
    val response = call.execute()
    assertThat(response.body.string()).isEqualTo("success")
  }

  /**
   * Tests that use this will fail unless boot classpath is set. Ex. `-Xbootclasspath/p:/tmp/alpn-boot-8.0.0.v20140317`
   */
  private fun enableProtocol(protocol: Protocol) {
    enableTls()
    client =
      client
        .newBuilder()

          while (true) {
            try {
              e = q.poll(deadline - System.nanoTime(), NANOSECONDS);
              break;
            } catch (InterruptedException ex) {
              interrupted = true; // note interruption and retry
            }
          }
          if (e == null) {
            break; // we already waited enough, and there are no more elements in sight

Uma imagem de contêiner é comparável ao arquivo de **programa** e seus conteúdos, ex.: `python` e algum arquivo `main.py`.

                    char[] both = {character, low};
                    c = Character.codePointAt(both, 0);
                    i++;
                } catch (IndexOutOfBoundsException ex) {
                    // high surrogate without low surrogate. Not a lot we can do here except treat it as a regular
                    // character
                }
            }

            if (c == '.') {

      if (end == -1) {
        end = ipString.length();
      }
      try {
        bytes[i] = parseOctet(ipString, start, end);
      } catch (NumberFormatException ex) {
        return null;
      }
      start = end + 1;
    }

    return bytes;
  }

  private static byte @Nullable [] textToNumericFormatV6(String ipString) {

Levaria o mesmo tempo para finalizar com ou sem turnos (concorrência) e você teria feito o mesmo tanto de trabalho.

Mas nesse caso, se você trouxesse os 8 ex-caixas / cozinheiros / agora-faxineiros, e cada um deles (mais você) pudessem dividir a casa para limpá-la, vocês fariam toda a limpeza em **paralelo**, com a ajuda extra, e terminariam muito mais cedo.

            int level = Trans2QueryFSInformationResponse.SMB_FS_FULL_SIZE_INFORMATION;
            try {
                return queryFSInformation(level);
            } catch (final SmbException ex) {
                switch (ex.getNtStatus()) {
                case NtStatus.NT_STATUS_INVALID_INFO_CLASS:
                case NtStatus.NT_STATUS_UNSUCCESSFUL: // NetApp Filer

It would take the same amount of time to finish with or without turns (concurrency) and you would have done the same amount of work.

But in this case, if you could bring the 8 ex-cashier/cooks/now-cleaners, and each one of them (plus you) could take a zone of the house to clean it, you could do all the work in **parallel**, with the extra help, and finish much sooner.

Cela prendrait autant de temps pour finir avec ou sans sections (concurrence) et vous auriez effectué la même quantité de travail.

Mais dans ce cas, si pouviez amener 8 ex-serveurs/cuisiniers/devenus-nettoyeurs 👨‍🍳👨‍🍳👨‍🍳👨‍🍳👨‍🍳👨‍🍳👨‍🍳👨‍🍳, et que chacun d'eux (plus vous) pouvait prendre une zone de la maison pour la nettoyer, vous pourriez faire tout le travail en parallèle, et finir plus tôt.