private int cursor = -1;
    private int nextCursor = -1;
    private int expectedModCount = modCount;
    // The same element is not allowed in both forgetMeNot and skipMe, but duplicates are allowed in
    // either of them, up to the same multiplicity as the queue.
    private @Nullable Queue<E> forgetMeNot;
    private @Nullable List<E> skipMe;
    private @Nullable E lastFromForgetMeNot;

   * whose elements are the result of applying {@code elementFunction} to the inputs, with counts
   * equal to the result of applying {@code countFunction} to the inputs.
   *
   * <p>If the mapped elements contain duplicates (according to {@code comparator}), the first
   * occurrence in encounter order appears in the resulting multiset, with count equal to the sum of

   * inputs, with counts equal to the result of applying {@code countFunction} to the inputs.
   * Elements are added in encounter order.
   *
   * <p>If the mapped elements contain duplicates (according to {@link Object#equals}), the element
   * will be added more than once, with the count summed over all appearances of the element.
   *

   * inputs, with counts equal to the result of applying {@code countFunction} to the inputs.
   * Elements are added in encounter order.
   *
   * <p>If the mapped elements contain duplicates (according to {@link Object#equals}), the element
   * will be added more than once, with the count summed over all appearances of the element.
   *

    private int cursor = -1;
    private int nextCursor = -1;
    private int expectedModCount = modCount;
    // The same element is not allowed in both forgetMeNot and skipMe, but duplicates are allowed in
    // either of them, up to the same multiplicity as the queue.
    private @Nullable Queue<E> forgetMeNot;
    private @Nullable List<E> skipMe;
    private @Nullable E lastFromForgetMeNot;

    assertIntact(q);
    q.remove(9);
    q.remove(11);
    q.remove(10);
    // Now we're in the critical state: [1, 15, 13, 8, 14]
    // Removing 8 while iterating caused duplicates in iteration result.
    List<Integer> result = Lists.newArrayListWithCapacity(initial.size());
    for (Iterator<Integer> iter = q.iterator(); iter.hasNext(); ) {
      Integer value = iter.next();
      result.add(value);

// DeleteObjects deletes objects/versions in bulk, this function will still automatically split objects list
// into smaller bulks if some object names are found to be duplicated in the delete list, splitting
// into smaller bulks will avoid holding twice the write lock of the duplicated object names.
func (er erasureObjects) DeleteObjects(ctx context.Context, bucket string, objects []ObjectToDelete, opts ObjectOptions) ([]DeletedObject, []error) {

   * whose elements are the result of applying {@code elementFunction} to the inputs, with counts
   * equal to the result of applying {@code countFunction} to the inputs.
   *
   * <p>If the mapped elements contain duplicates (according to {@code comparator}), the first
   * occurrence in encounter order appears in the resulting multiset, with count equal to the sum of

    }
    return !iterable.iterator().hasNext();
  }

  /**
   * Returns an iterable over the merged contents of all given {@code iterables}. Equivalent entries
   * will not be de-duplicated.
   *
   * <p>Callers must ensure that the source {@code iterables} are in non-descending order as this
   * method does not sort its input.
   *

        // We only check for groupId/artifactId/version/classifier cause if there is another
        // module with the same groupId/artifactId/version/classifier this will fail the build
        // earlier like "Project '...' is duplicated in the reactor.
        // So it is sufficient to check only groupId/artifactId/version/classifier and not the
        // packaging type.
        for (Dependency dependency : dependencies) {