import org.checkerframework.checker.nullness.qual.Nullable;

/**
 * A {@code Multiset} implementation with predictable iteration order. Its iterator orders elements
 * according to when the first occurrence of the element was added. When the multiset contains
 * multiple instances of an element, those instances are consecutive in the iteration order. If all
 * occurrences of an element are removed, after which that element is added to the multiset, the

     */
    public MultiIterator(final Iterator<E>... iterators) {
        assertArgumentNotNull("iterators", iterators);
        this.iterators = iterators;
    }

    @Override
    public boolean hasNext() {
        for (; index < iterators.length; ++index) {
            if (iterators[index].hasNext()) {
                return true;
            }
        }
        return false;
    }

   *
   * <p><i>Notes:</i> This is an implementation of the algorithm for Lexicographical Permutations
   * Generation, described in Knuth's "The Art of Computer Programming", Volume 4, Chapter 7,
   * Section 7.2.1.2. The iteration order follows the lexicographical order. This means that the
   * first permutation will be in ascending order, and the last will be in descending order.
   *

    assertEquals(1, Iterators.size(registry.getSubscribers(1)));

    registry.register(new IntegerSubscriber());
    assertEquals(3, Iterators.size(registry.getSubscribers("")));
    assertEquals(1, Iterators.size(registry.getSubscribers(new Object())));
    assertEquals(2, Iterators.size(registry.getSubscribers(1)));
  }

  public void testGetSubscribers_returnsImmutableSnapshot() {

    assertEquals(1, Iterators.size(registry.getSubscribers(1)));

    registry.register(new IntegerSubscriber());
    assertEquals(3, Iterators.size(registry.getSubscribers("")));
    assertEquals(1, Iterators.size(registry.getSubscribers(new Object())));
    assertEquals(2, Iterators.size(registry.getSubscribers(1)));
  }

  public void testGetSubscribers_returnsImmutableSnapshot() {

import com.google.caliper.BeforeExperiment;
import com.google.caliper.Benchmark;
import com.google.caliper.Param;
import java.util.Set;

/**
 * Very simple powerSet iteration benchmark.
 *
 * @author Kevin Bourrillion
 */
public class PowerSetBenchmark {
  @Param({"2", "4", "8", "16"})
  int elements;

  Set<Set<Integer>> powerSet;

  @BeforeExperiment
  void setUp() {

 *       is modified.
 *   <li><b>Null-hostility.</b> This collection will never contain a null element.
 *   <li><b>Deterministic iteration.</b> The iteration order is always well-defined, depending on
 *       how the collection was created. Typically this is insertion order unless an explicit

## Dependencies for groups of *path operations*

		if n := atomic.LoadUint64(&o.operations[i]); n > 0 {
			m.LifeTimeOps[i.String()] = n
		}
	}
	if len(m.LifeTimeOps) == 0 {
		m.LifeTimeOps = nil
	}

	m.LastMinute.Operations = make(map[string]madmin.TimedAction, osMetricLast)
	for i := osMetric(0); i < osMetricLast; i++ {
		lm := o.latency[i].total()
		if lm.N > 0 {
			m.LastMinute.Operations[i.String()] = lm.asTimedAction()
		}
	}

Benchmarks can use the new [B.Loop] method in `for b.Loop() { ... }` loops to determine if iteration should continue....