* code, running tests, packaging the project, and deploying it. Executing a phase
 * triggers all preceding phases, ensuring that each step of the build process is
 * completed in the correct order. The three main lifecycles in Maven are
 * {@link #DEFAULT default}, {@link #CLEAN clean}, and {@link #SITE site}, with the
 * {@code default} lifecycle being the most commonly used for project builds.
 *
 * @since 4.0.0
 */

    Iterator<String> iterator = asList("one", "two", "three", "four", "five").iterator();
    IllegalArgumentException expected =
        assertThrows(IllegalArgumentException.class, () -> getOnlyElement(iterator));
    assertThat(expected)
        .hasMessageThat()
        .isEqualTo("expected one element but was: <one, two, three, four, five>");
  }

        // and overlong 2-byte form.
        if (byte1 < (byte) 0xC2 || bytes[index++] > (byte) 0xBF) {
          return false;
        }
      } else if (byte1 < (byte) 0xF0) {
        // Three-byte form.
        if (index + 1 >= end) {
          return false;
        }
        int byte2 = bytes[index++];
        if (byte2 > (byte) 0xBF
            // Overlong? 5 most significant bits must not all be zero.

   The root credentials can now be changed easily.

> Does this mean I need an enterprise KMS setup to run MinIO (securely)?

No, MinIO does not depend on any third-party KMS provider. You have three options here:

- Run MinIO without a KMS. In this case all IAM data will be stored in plain-text.
- Run MinIO with a single secret key. MinIO supports a static cryptographic key

    Iterator<String> iterator = asList("one", "two", "three", "four", "five").iterator();
    IllegalArgumentException expected =
        assertThrows(IllegalArgumentException.class, () -> getOnlyElement(iterator));
    assertThat(expected)
        .hasMessageThat()
        .isEqualTo("expected one element but was: <one, two, three, four, five>");
  }

Son más relevantes para versiones más antiguas, antes de que OpenAPI 3.1.0 estuviera disponible.

Puedes considerar esto una breve lección de **historia** de OpenAPI y JSON Schema. 🤓

///

/// warning | Advertencia

Estos son detalles muy técnicos sobre los estándares **JSON Schema** y **OpenAPI**.

   */
  public static <T extends @Nullable Object> Iterable<T> concat(
      Iterable<? extends T> a, Iterable<? extends T> b) {
    return FluentIterable.concat(a, b);
  }

  /**
   * Combines three iterables into a single iterable. The returned iterable has an iterator that
   * traverses the elements in {@code a}, followed by the elements in {@code b}, followed by the

      Combiner2<V1, V2> whenAllSucceed(ClosingFuture<V1> future1, ClosingFuture<V2> future2) {
    return new Combiner2<>(future1, future2);
  }

  /**
   * Starts specifying how to combine three {@link ClosingFuture}s into a single pipeline, assuming
   * they all succeed. If any fail, the resulting pipeline will fail.
   *
   * <p>Calling this method allows you to use lambdas or method references typed with the types of

      cp >>>= 2;
      dest[2] = upperHexDigits[cp & 0xF];
      cp >>>= 4;
      dest[1] = upperHexDigits[0xC | cp];
      return dest;
    } else if (cp <= 0xffff) {
      // Three byte UTF-8 characters [cp >= 0x800 && cp <= 0xffff]
      // Start with "%E-%--%--" and fill in the blanks
      char[] dest = new char[9];
      dest[0] = '%';
      dest[1] = 'E';
      dest[3] = '%';

      this.elements = elements;
      this.duplicate = duplicate;
    }
  }

  /**
   * @return an array of the proper size with a duplicate element. The size must be at least three.
   */
  protected ArrayWithDuplicate<E> createArrayWithDuplicateElement() {
    E[] elements = createSamplesArray();
    E duplicate = elements[(elements.length / 2) - 1];