object Credentials {
  /** Returns an auth credential for the Basic scheme. */
  @JvmStatic @JvmOverloads
  fun basic(
    username: String,
    password: String,
    charset: Charset = ISO_8859_1,
  ): String {
    val usernameAndPassword = "$username:$password"
    val encoded = usernameAndPassword.encode(charset).base64()
    return "Basic $encoded"
  }

    return {"username": credentials.username, "password": credentials.password}


client = TestClient(app)


def test_security_http_basic():
    response = client.get("/users/me", auth=("john", "secret"))
    assert response.status_code == 200, response.text
    assert response.json() == {"username": "john", "password": "secret"}


def test_security_http_basic_no_credentials():

        this.pager = value;
    }

    public String getPassword() {
        checkSpecifiedProperty("password");
        return convertEmptyToNull(password);
    }

    public void setPassword(String value) {
        registerModifiedProperty("password");
        this.password = value;
    }

    public String getPhysicalDeliveryOfficeName() {

            raise invalid_user_credentials_exc  # noqa: B904
        username, separator, password = data.partition(":")
        if not separator:
            raise invalid_user_credentials_exc
        return HTTPBasicCredentials(username=username, password=password)


class HTTPBearer(HTTPBase):
    """
    HTTP Bearer token authentication.

    ## Usage

        ComponentUtil.getLdapManager().delete(user);
    }

    @Override
    public boolean changePassword(final String username, final String password) {
        final boolean changed = ComponentUtil.getLdapManager().changePassword(username, password);
        return !changed || ComponentUtil.getFessConfig().isLdapAdminSyncPassword();
    }

    @Override
    public User load(final User user) {

`secrets.compare_digest()` 需要仅包含 ASCII 字符（英语字符）的 `bytes` 或 `str`，这意味着它不适用于像`á`一样的字符，如 `Sebastián`。

为了解决这个问题，我们首先将 `username` 和 `password` 转换为使用 UTF-8 编码的 `bytes` 。

然后我们可以使用 `secrets.compare_digest()` 来确保 `credentials.username` 是 `"stanleyjobson"`，且 `credentials.password` 是`"swordfish"`。

//// tab | Python 3.9+

```Python hl_lines="1  12-24"
{!> ../../docs_src/security/tutorial007_an_py39.py!}
```

////

class UserIn(UserBase):
    password: str


class UserOut(UserBase):
    pass


class UserInDB(UserBase):
    hashed_password: str


def fake_password_hasher(raw_password: str):
    return "supersecret" + raw_password


def fake_save_user(user_in: UserIn):
    hashed_password = fake_password_hasher(user_in.password)

                                    <label for="password" class="col-sm-3 text-sm-right col-form-label"><la:message
                                            key="labels.file_auth_password"/></label>
                                    <div class="col-sm-9">
                                        <la:errors property="password"/>
                                        <la:password styleId="password" property="password" styleClass="form-control"/>

////

Zum Beispiel stellt eine der Möglichkeiten, die OAuth2 Spezifikation zu verwenden (genannt <abbr title='„Passwort-Fluss“'>„password flow“</abbr>), die Bedingung, einen `username` und ein `password` als Formularfelder zu senden.

Die <abbr title="Specification – Spezifikation">Spec</abbr> erfordert, dass die Felder exakt `username` und `password` genannt werden und als Formularfelder, nicht JSON, gesendet werden.

    current_password_bytes = credentials.password.encode("utf8")
    correct_password_bytes = b"swordfish"
    is_correct_password = secrets.compare_digest(
        current_password_bytes, correct_password_bytes
    )
    if not (is_correct_username and is_correct_password):
        raise HTTPException(
            status_code=status.HTTP_401_UNAUTHORIZED,
            detail="Incorrect username or password",