Verwenden Sie dazu `yield` statt `return` und schreiben Sie die zusätzlichen Schritte / den zusätzlichen Code danach.

/// tip | "Tipp"

Stellen Sie sicher, dass Sie `yield` nur einmal pro Abhängigkeit verwenden.

///

/// note | "Technische Details"

Jede Funktion, die dekoriert werden kann mit:

* 🌐 Add Spanish translation for `docs/es/docs/advanced/security/index.md`. PR [#2278](https://github.com/tiangolo/fastapi/pull/2278) by [@Xaraxx](https://github.com/Xaraxx).
* 🌐 Add Spanish translation for `docs/es/docs/advanced/response-headers.md`. PR [#2276](https://github.com/tiangolo/fastapi/pull/2276) by [@Xaraxx](https://github.com/Xaraxx).

        do {
            try {
                send(request, response, config.getNetbiosRetryTimeout());
            }
            catch ( InterruptedIOException ioe ) {
                // second query thread to finish gets interrupted so this is expected
                if ( log.isTraceEnabled() ) {
                    log.trace("Failed to send nameservice request for " + name.name, ioe);
                }

n(a){return!1!==a&&(a=a||"fx"),this.each(function(){var e,t=_.get(this),n=t[a+"queue"],r=t[a+"queueHooks"],i=ce.timers,o=n?n.length:0;for(t.finish=!0,ce.queue(this,a,[]),r&&r.stop&&r.stop.call(this,!0),e=i.length;e--;)i[e].elem===this&&i[e].queue===a&&(i[e].anim.stop(!0),i.splice(e,1));for(e=0;e<o;e++)n[e]&&n[e].finish&&n[e].finish.call(this);delete t.finish})}}),ce.each(["toggle","show","hide"],function(e,r){var i=ce.fn[r];ce.fn[r]=function(e,t,n){return null==e||"boolean"==typeof e?i.apply(thi...

labels.advance_search_filetype_powerpoint	=	MS PowerPoint
labels.advance_search_occt	=	Termes affichés
labels.advance_search_occt_default	=	n'importe où dans la page
labels.advance_search_occt_allintitle	=	dans le titre de la page
labels.advance_search_occt_allinurl	=	dans l'url de la page
labels.advance_search_sitesearch	=	Site ou domaine
labels.advance_search_timestamp	=	Dernière mise à jour

   *
   * This test yields threads to force the decision of plan1 to be deliberate and not lucky. In
   * particular, we set up this sequence of events:
   *
   *  1. take plan 0
   *  3. plan 0 connects
   *  4. finish taking plan 1
   *
   * https://github.com/square/okhttp/issues/7152
   */
  @Test
  fun reusePlanAndNewConnectRace() {
    val plan0 = routePlanner.addPlan()
    plan0.tcpConnectDelayNanos = 250.ms

	h.status.Store(statusClosed)
	h.storeCtxCancel()

	// Wait for messages to be sent...
	h.wg.Wait()

	// Set logch to nil and close it.
	// This will block all Send operations,
	// and finish the existing ones.
	// All future ones will be discarded.
	h.logChMu.Lock()
	xioutil.SafeClose(h.logCh)
	h.logCh = nil
	h.logChMu.Unlock()

	r.setErr(errors.New("reset called"), true)
	if r.block {
		r.readCond.Broadcast()
		r.writeCond.Broadcast()
	}

	// Unlock the mutex so readers/writers can finish.
	r.mu.Unlock()
	r.wg.Wait()
	r.mu.Lock()
	r.r = 0
	r.w = 0
	r.err = nil
	r.isFull = false
}

// WriteCloser returns a WriteCloser that writes to the ring buffer.

n(a){return a!==!1&&(a=a||"fx"),this.each(function(){var b,c=L.get(this),d=c[a+"queue"],e=c[a+"queueHooks"],f=n.timers,g=d?d.length:0;for(c.finish=!0,n.queue(this,a,[]),e&&e.stop&&e.stop.call(this,!0),b=f.length;b--;)f[b].elem===this&&f[b].queue===a&&(f[b].anim.stop(!0),f.splice(b,1));for(b=0;g>b;b++)d[b]&&d[b].finish&&d[b].finish.call(this);delete c.finish})}}),n.each(["toggle","show","hide"],function(a,b){var c=n.fn[b];n.fn[b]=function(a,d,e){return null==a||"boolean"==typeof a?c.apply(this,ar...

      Executor executor) {
    return AbstractCatchingFuture.createAsync(input, exceptionType, fallback, executor);
  }

  /**
   * Returns a future that delegates to another but will finish early (via a {@link
   * TimeoutException} wrapped in an {@link ExecutionException}) if the specified duration expires.
   *
   * <p>The delegate future is interrupted and cancelled if it times out.
   *