t.Fatalf("%d: %v", i, err)
		}

		// repr.Println(s, repr.Indent("  "), repr.OmitEmpty(true))
	}
}

func TestSqlLexerArithOps(t *testing.T) {
	s := bytes.NewBuffer([]byte("year from select month hour distinct"))
	lex, err := sqlLexer.Lex(s)
	if err != nil {
		t.Fatal(err)
	}
	tokens, err := lexer.ConsumeAll(lex)
	if err != nil {
		t.Fatal(err)
	}
	if len(tokens) != 7 {

      } else {
        return contains(element) ? unfiltered.remove(element, occurrences) : 0;
      }
    }
  }

  /**
   * Returns the expected number of distinct elements given the specified elements. The number of
   * distinct elements is only computed if {@code elements} is an instance of {@code Multiset};
   * otherwise the default value of 11 is returned.
   */

      } else {
        return contains(element) ? unfiltered.remove(element, occurrences) : 0;
      }
    }
  }

  /**
   * Returns the expected number of distinct elements given the specified elements. The number of
   * distinct elements is only computed if {@code elements} is an instance of {@code Multiset};
   * otherwise the default value of 11 is returned.
   */

 *       hand, is multiple-use, and does implement {@link Iterable}.
 *   <li>Streams offer many features not found here, including {@code min/max}, {@code distinct},
 *       {@code reduce}, {@code sorted}, the very powerful {@code collect}, and built-in support for
 *       parallelizing stream operations.

   * inequality.
   */
  protected final <T> void setDefault(Class<T> type, T value) {
    tester.setDefault(type, value);
  }

  /**
   * Sets two distinct values for {@code type}. These values can be used for both null pointer
   * testing and equals testing.
   *
   * @since 17.0
   */
  protected final <T> void setDistinctValues(Class<T> type, T value1, T value2) {

    }

    @Override
    public Multiset<K> create(Object... elements) {
      /*
       * This is nasty and complicated, but it's the only way to make sure keys get mapped to enough
       * distinct values.
       */
      Entry<?, ?>[] entries = new Entry<?, ?>[elements.length];
      Map<K, Iterator<V>> valueIterators = new HashMap<>();
      for (int i = 0; i < elements.length; i++) {

   *
   * <p><b>Warning: do not depend</b> on the behavior of this method.
   *
   * <p>Historically, {@code Equivalence} instances in this library have implemented this method to
   * recognize certain cases where distinct {@code Equivalence} instances would in fact behave
   * identically. However, as code migrates to {@code java.util.function}, that behavior will
   * disappear. It is best not to depend on it.
   */
  @Override

   * Arrays#asList(Object[])}. The list supports {@link List#set(int, Object)}, but any attempt to
   * set a value to {@code null} will result in a {@link NullPointerException}.
   *
   * <p>There are at most two distinct objects in this list, {@code (Boolean) true} and {@code
   * (Boolean) false}. Java guarantees that those are always represented by the same objects.
   *
   * <p>The returned list is serializable.
   *

   * Arrays#asList(Object[])}. The list supports {@link List#set(int, Object)}, but any attempt to
   * set a value to {@code null} will result in a {@link NullPointerException}.
   *
   * <p>There are at most two distinct objects in this list, {@code (Boolean) true} and {@code
   * (Boolean) false}. Java guarantees that those are always represented by the same objects.
   *
   * <p>The returned list is serializable.
   *

   * It will never change, even if the maps change at a later time.
   *
   * <p>Since this method uses {@code TreeMap} instances internally, the keys of the right map must
   * all compare as distinct according to the comparator of the left map.
   *
   * <p><b>Note:</b>If you only need to know whether two sorted maps have the same mappings, call
   * {@code left.equals(right)} instead of this method.
   *