}

  @Test fun uncaughtException() {
    val testRule = OkHttpClientTestRule()
    testRule.beforeEach(extensionContext)

    val thread =
      object : Thread() {
        override fun run() {
          throw RuntimeException("boom!")
        }
      }
    thread.start()
    thread.join()

    assertFailsWith<AssertionError> {
      testRule.afterEach(extensionContext)
    }.also { expected ->

  // unnecessary allocations each Execute call, we keep one heap-allocated
  // version for the thread.
  StatusPtr status_ TF_GUARDED_BY(execution_mutex_);

  const std::string device_;
  ExecutorPtr executor_ TF_GUARDED_BY(execution_mutex_);
  mutable OpPtr op_ TF_GUARDED_BY(execution_mutex_);
  std::unique_ptr<Thread> thread_;
};

DeviceThread::~DeviceThread() {
  {
    tensorflow::mutex_lock l(execution_mutex_);

   * The particular nature and strength of the guarantees made by the proxy is
   * implementation-dependent. However, it is important that each of the methods on the target
   * object behaves appropriately when its thread is interrupted.
   *
   * <p>For example, to return the value of {@code target.someMethod()}, but substitute {@code
   * DEFAULT_VALUE} if this method call takes over 50 ms, you can use this code:
   *
   * <pre>

    final CountDownLatch doneSignal = new CountDownLatch(1);

    Thread thread =
        new Thread() {
          @Override
          public void run() {
            try {
              cacheRef.get().getUnchecked(3);
            } finally {
              doneSignal.countDown();
            }
          }
        };
    thread.setUncaughtExceptionHandler(
        new UncaughtExceptionHandler() {

    final CountDownLatch doneSignal = new CountDownLatch(1);

    Thread thread =
        new Thread() {
          @Override
          public void run() {
            try {
              cacheRef.get().getUnchecked(3);
            } finally {
              doneSignal.countDown();
            }
          }
        };
    thread.setUncaughtExceptionHandler(
        new UncaughtExceptionHandler() {

 * example involving two locks and two threads, deadlock occurs when one thread acquires Lock A, and
 * then Lock B, while another thread acquires Lock B, and then Lock A:
 *
 * <pre>
 * Thread1: acquire(LockA) --X acquire(LockB)
 * Thread2: acquire(LockB) --X acquire(LockA)
 * </pre>
 *
 * <p>Neither thread will progress because each is waiting for the other. In more complex

    }


    private static void interruptThreadSafely ( QueryThread thread ) {
        try {
            thread.interrupt();
        }
        catch ( SecurityException e ) {
            e.printStackTrace();
        }
    }


    private static void joinThread ( Thread thread ) {
        try {
            thread.join();
        }
        catch ( InterruptedException e ) {

  private fun sleep(delayMillis: Int) {
    try {
      Thread.sleep(delayMillis.toLong())
    } catch (e: InterruptedException) {
      Thread.currentThread().interrupt()
    }
  }

  private fun cancelLater(
    call: Call,
    delayMillis: Int,
  ): CountDownLatch {
    val latch = CountDownLatch(1)
    Thread {
      sleep(delayMillis)
      if (cancelMode == CANCEL) {

              @Override
              public Integer call() {
                return Thread.currentThread().getStackTrace().length;
              }
            },
            directExecutor());
    settableFuture.set(null);
    assertThat(getDone(stackDepthCheck))
        .isLessThan(Thread.currentThread().getStackTrace().length + 100);
  }

  }

  @J2ktIncompatible
  @GwtIncompatible // Thread.interrupt
  public void testGetUnchecked_interrupted() {
    Thread.currentThread().interrupt();
    try {
      assertEquals("foo", getUnchecked(immediateFuture("foo")));
      assertTrue(Thread.currentThread().isInterrupted());
    } finally {
      Thread.interrupted();
    }
  }

  public void testGetUnchecked_cancelled() {