* @throws IOException
     */
    @Test
    void testGetOutputStreamCachesData() throws IOException {
        // Arrange
        // Enable output mode
        when(mockConnection.getDoOutput()).thenReturn(true);
        ntlmConnection.setDoOutput(true);

        // Mock initial connection's output stream (needed for CacheStream)

    waiter.start();
    waiter.awaitWaiting();

    future.set(1);
    waiter.join();
  }

  @J2ktIncompatible // TODO(b/324550390): Enable
  public void testSetNull() throws Exception {
    future.set(null);
    assertSuccessful(future, null);
  }

  @SuppressWarnings("nullness") // test of a bogus call

            "type": "type_error.integer"
        }
    ]
}
```

将得到如下文本内容：

```
Validation errors:
Field: ('path', 'item_id'), Error: Input should be a valid integer, unable to parse string as an integer
```

### 覆盖 `HTTPException` 错误处理器 { #override-the-httpexception-error-handler }

同理，也可以覆盖 `HTTPException` 的处理器。

例如，只为这些错误返回纯文本响应，而不是 JSON：

                    {"data": "examples example_examples 1"},
                    {"data": "examples example_examples 2"},
                ],
            ),
        ):
            return item

    # TODO: enable these tests once/if Form(embed=False) is supported
    # TODO: In that case, define if File() should support example/examples too
    # @app.post("/form_example")
    # def form_example(firstname: str = Form(example="John")):

   * resulting text.
   *
   * <p>If the character does not need to be escaped, this method should return {@code null}, rather
   * than an array containing the character representation of the code point. This enables the
   * escaping algorithm to perform more efficiently.
   *
   * <p>If the implementation of this method cannot correctly handle a particular code point then it

     * </p>
     */
    public DataSerializer() {
        kryoThreadLocal = ThreadLocal.withInitial(() -> {
            final Kryo kryo = new Kryo();
            // Enable registration requirement for security - only registered classes can be deserialized
            kryo.setRegistrationRequired(true);
            if (logger.isDebugEnabled()) {
                kryo.setWarnUnregisteredClasses(true);

    } else if (test instanceof TestCase) {
      TestCase testCase = (TestCase) test;
      return getMethod(testCase.getClass(), testCase.getName());
    } else {
      throw new IllegalArgumentException("unable to extract method from test: not a TestCase.");
    }
  }

  protected TestSuite makeSuiteForTesterClass(Class<? extends AbstractTester<?>> testerClass) {
    TestSuite candidateTests = new TestSuite(testerClass);

            "type": "type_error.integer"
        }
    ]
}
```

ви отримаєте текстову версію:

```
Validation errors:
Field: ('path', 'item_id'), Error: Input should be a valid integer, unable to parse string as an integer
```

### Перевизначення обробника помилок `HTTPException` { #override-the-httpexception-error-handler }

Аналогічно, ви можете перевизначити обробник `HTTPException`.

        }
    ]
}
```

şu şekilde bir metin (text) versiyonu alırsınız:

```
Validation errors:
Field: ('path', 'item_id'), Error: Input should be a valid integer, unable to parse string as an integer
```

### `HTTPException` Hata Handler’ını Override Etmek { #override-the-httpexception-error-handler }

Benzer şekilde `HTTPException` handler’ını da override edebilirsiniz.

```JSON
{
  "detail": [
    {
      "type": "int_parsing",
      "loc": [
        "path",
        "item_id"
      ],
      "msg": "Input should be a valid integer, unable to parse string as an integer",
      "input": "foo"
    }
  ]
}
```

çünkü path parametresi `item_id`, `int` olmayan `"foo"` değerine sahipti.