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docs/de/docs/how-to/conditional-openapi.md
Wenn Sie Ihre API sichern möchten, gibt es mehrere bessere Dinge, die Sie tun können, zum Beispiel:
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guava/src/com/google/common/util/concurrent/ForwardingBlockingQueue.java
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docs/pt/docs/how-to/conditional-openapi.md
Ocultar a documentação apenas torna mais difícil entender como interagir com sua API e pode dificultar sua depuração na produção. Pode ser considerado simplesmente uma forma de <a href="https://en.wikipedia.org/wiki/Security_through_obscurity" class="external-link" target="_blank">Segurança através da obscuridade</a>. Se você quiser proteger sua API, há várias coisas melhores que você pode fazer, por exemplo:
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android/guava/src/com/google/common/collect/ForwardingSortedSetMultimap.java
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guava/src/com/google/common/collect/TreeBasedTable.java
* concurrently and one of the threads modifies the table, it must be synchronized externally. * * <p>See the Guava User Guide article on <a href= * "https://github.com/google/guava/wiki/NewCollectionTypesExplained#table">{@code Table}</a>. * * @author Jared Levy * @author Louis Wasserman * @since 7.0 */ @GwtCompatible(serializable = true) @ElementTypesAreNonnullByDefault
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docs/ru/docs/deployment/https.md
* Однако, у этой проблемы есть **решение**. * Существует **расширение** протокола **TLS** (который работает на уровне TCP, то есть до HTTP) называемое **<a href="https://en.wikipedia.org/wiki/Server_Name_Indication" class="external-link" target="_blank"><abbr title="Указание имени сервера">SNI</abbr></a>**.
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docs/en/docs/tutorial/encoder.md
For example, it doesn't receive `datetime` objects, as those are not compatible with JSON. So, a `datetime` object would have to be converted to a `str` containing the data in <a href="https://en.wikipedia.org/wiki/ISO_8601" class="external-link" target="_blank">ISO format</a>. The same way, this database wouldn't receive a Pydantic model (an object with attributes), only a `dict`. You can use `jsonable_encoder` for that.
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docs/em/docs/tutorial/path-operation-configuration.md
👆 💪 ✍ <a href="https://en.wikipedia.org/wiki/Markdown" class="external-link" target="_blank">✍</a> #️⃣ , ⚫️ 🔜 🔬 & 🖥 ☑ (✊ 🔘 🏧 #️⃣ 📐). //// tab | 🐍 3️⃣.6️⃣ & 🔛 ```Python hl_lines="19-27"
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Sun Oct 06 20:36:54 UTC 2024 - 5.2K bytes - Viewed (0) -
docs/ko/docs/advanced/response-directly.md
## 사용자 정의 `Response` 반환하기 위 예제는 필요한 모든 부분을 보여주지만, 아직 유용하지는 않습니다. 사실 데이터를 직접 반환하면 **FastAPI**가 이를 `JSONResponse`에 넣고 `dict`로 변환하는 등 모든 작업을 자동으로 처리합니다. 이제, 사용자 정의 응답을 반환하는 방법을 알아보겠습니다. 예를 들어 <a href="https://en.wikipedia.org/wiki/XML" class="external-link" target="_blank">XML</a> 응답을 반환하고 싶다고 가정해보겠습니다. XML 내용을 문자열에 넣고, 이를 `Response`에 넣어 반환할 수 있습니다: ```Python hl_lines="1 18" {!../../docs_src/response_directly/tutorial002.py!} ``` ## 참고 사항
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docs/zh/docs/advanced/response-directly.md
/// ## 返回自定义 `Response` 上面的例子展示了需要的所有部分,但还不够实用,因为你本可以只是直接返回 `item`,而**FastAPI** 默认帮你把这个 `item` 放到 `JSONResponse` 中,又默认将其转换成了 `dict`等等。 现在,让我们看看你如何才能返回一个自定义的响应。 假设你想要返回一个 <a href="https://en.wikipedia.org/wiki/XML" class="external-link" target="_blank">XML</a> 响应。 你可以把你的 XML 内容放到一个字符串中,放到一个 `Response` 中,然后返回。 ```Python hl_lines="1 18" {!../../docs_src/response_directly/tutorial002.py!} ``` ## 说明
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