Iterators.transform(
                  predecessors().iterator(),
                  (N predecessor) -> EndpointPair.ordered(predecessor, thisNode)),
              Iterators.transform(
                  successors().iterator(),
                  (N successor) -> EndpointPair.ordered(thisNode, successor)));
    } else {
      resultWithDoubleSelfLoop =
          Iterators.transform(

 * collector by only using a constant number of internal objects.
 *
 * <p>If there are no removals, then iteration order for the {@link #entrySet}, {@link #keySet}, and
 * {@link #values} views is the same as insertion order. Any removal invalidates any ordering
 * guarantees.
 *
 * <p>This class should not be assumed to be universally superior to {@code java.util.HashMap}.

        void testDecodeNoReferrals() {
            // Prepare test data: pathConsumed=0, numReferrals=0, tflags=0
            byte[] testBuffer = new byte[8];
            ByteBuffer bb = ByteBuffer.wrap(testBuffer).order(ByteOrder.LITTLE_ENDIAN);
            bb.putShort((short) 0); // pathConsumed (will be divided by 2)
            bb.putShort((short) 0); // numReferrals
            bb.putShort((short) 0); // tflags

    }

    @Test
    @DisplayName("Should return consistent ordinal values")
    void testOrdinalValues() {
        // Ordinal values should be consistent with enum declaration order
        assertTrue(DialectVersion.SMB1.ordinal() < DialectVersion.SMB202.ordinal());
        assertTrue(DialectVersion.SMB202.ordinal() < DialectVersion.SMB210.ordinal());

   * were inserted into the builder, equivalently to {@code LinkedHashMap}. For example, in the
   * above example, {@code WORD_TO_INT.entrySet()} is guaranteed to iterate over the entries in the
   * order {@code "one"=1, "two"=2, "three"=3}, and {@code keySet()} and {@code values()} respect
   * the same order. If you want a different order, consider using {@link ImmutableSortedMap} to

   * for some instances where the statistics are mathematically equal, including instances
   * constructed from the same values in a different order... or (in the general case) even in the
   * same order. (It is guaranteed to return true for instances constructed from the same values in
   * the same order if {@code strictfp} is in effect, or if the system architecture guarantees
   * {@code strictfp}-like semantics.)
   */
  @Override

	}

	var names []string
	DB.Table("users").Where("name like ?", "distinct%").Order("name").Pluck("name", &names)
	AssertEqual(t, names, []string{"distinct", "distinct", "distinct", "distinct-2", "distinct-3"})

	var names1 []string
	DB.Model(&User{}).Where("name like ?", "distinct%").Distinct().Order("name").Pluck("Name", &names1)

	AssertEqual(t, names1, []string{"distinct", "distinct-2", "distinct-3"})

{% for sponsor in sponsors.gold -%}
<a href="{{ sponsor.url }}" target="_blank" title="{{ sponsor.title }}"><img src="{{ sponsor.img }}" style="border-radius:15px"></a>
{% endfor -%}
{%- for sponsor in sponsors.silver -%}
<a href="{{ sponsor.url }}" target="_blank" title="{{ sponsor.title }}"><img src="{{ sponsor.img }}" style="border-radius:15px"></a>
{% endfor %}
{% endif %}

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        scoreUpdater.addScoreBooster(booster2);
        scoreUpdater.addScoreBooster(booster3);

        // Clear execution order before test
        PriorityTrackingBooster.clearExecutionOrder();

        scoreUpdater.execute();

        // Boosters should be executed in priority order (3, 2, 1)
        List<Integer> executionOrder = PriorityTrackingBooster.getExecutionOrder();
        assertEquals(3, executionOrder.size());

    Object[] actual = getList().toArray();
    assertArrayEquals("toArray() order should match list", createOrderedArray(), actual);
  }

  @CollectionSize.Require(absent = ZERO)
  public void testToArray_tooSmall() {
    Object[] actual = getList().toArray(new Object[0]);
    assertArrayEquals("toArray(tooSmall) order should match list", createOrderedArray(), actual);
  }

  public void testToArray_largeEnough() {