/**
 * A multiset which maintains the ordering of its elements, according to either their natural order
 * or an explicit {@link Comparator}. In all cases, this implementation uses {@link
 * Comparable#compareTo} or {@link Comparator#compare} instead of {@link Object#equals} to determine
 * equivalence of instances.
 *
 * <p><b>Warning:</b> The comparison must be <i>consistent with equals</i> as explained by the

#### Corrija com o `secrets.compare_digest()` { #fix-it-with-secrets-compare-digest }

Mas em nosso código já estamos utilizando o `secrets.compare_digest()`.

Resumindo, levará o mesmo tempo para comparar `stanleyjobsox` com `stanleyjobson` do que comparar `johndoe` com `stanleyjobson`. E o mesmo para a senha.

		t.Fatalf("Build count with select, but got %v", result.Statement.SQL.String())
	}

	var count4 int64
	if err := DB.Table("users").Joins("LEFT JOIN companies on companies.name = users.name").Where("users.name = ?", user1.Name).Count(&count4).Error; err != nil || count4 != 1 {
		t.Errorf("count with join, got error: %v, count %v", err, count4)
	}

	var count5 int64

  }

  // needed because otherwise Object.toString() calls hashCode()
  @Override
  public String toString() {
    return "DontHashMe" + value;
  }

  @Override
  public int compareTo(UnhashableObject o) {
    return Integer.compare(this.value, o.value);
  }

@GwtCompatible
final class UsingToStringOrdering extends Ordering<Object> implements Serializable {
  static final UsingToStringOrdering INSTANCE = new UsingToStringOrdering();

  @Override
  public int compare(Object left, Object right) {
    return left.toString().compareTo(right.toString());
  }

  // preserve singleton-ness, so equals() and hashCode() work correctly
  private Object readResolve() {
    return INSTANCE;
  }

  @Override

Harshavardhana <******@****.***> 1699046298 -0700

 *     seqNum = seq.getAndIncrement();
 *     this.entry = entry;
 *   }
 *
 *   public E getEntry() {
 *     return entry;
 *   }
 *
 *   public int compareTo(FIFOEntry<E> other) {
 *     int res = entry.compareTo(other.entry);
 *     if (res == 0 && other.entry != this.entry) {
 *       res = (seqNum < other.seqNum ? -1 : 1);
 *     }
 *     return res;
 *   }
 * }
 * }</pre>
 *

            @Override
            public int compare(K o1, K o2) {
              return ((Comparable) o1).compareTo(o2);
            }
          };
    }
    Iterator<Entry<K, V>> entryItr = navigableMap.entrySet().iterator();
    Entry<K, V> prevEntry = entryItr.next();
    while (entryItr.hasNext()) {
      Entry<K, V> nextEntry = entryItr.next();
      assertTrue(comparator.compare(prevEntry.getKey(), nextEntry.getKey()) < 0);

  @Override
  public int compareTo(Cut<C> that) {
    if (that == belowAll()) {
      return 1;
    }
    if (that == aboveAll()) {
      return -1;
    }
    int result = Range.compareOrThrow(endpoint, that.endpoint);
    if (result != 0) {
      return result;
    }
    // same value. below comes before above
    return Boolean.compare(this instanceof AboveValue, that instanceof AboveValue);
  }

  @Override
  @SuppressWarnings("unchecked") // TODO(kevinb): the right way to explain this??
  public int compare(Comparable<?> left, Comparable<?> right) {
    checkNotNull(left); // right null is caught later
    if (left == right) {
      return 0;
    }

    return ((Comparable<Object>) right).compareTo(left);
  }

  @Override
  public <S extends Comparable<?>> Ordering<S> reverse() {
    return Ordering.natural();