- Sort Score
- Result 10 results
- Languages All
Results 1 - 8 of 8 for swordfish (0.08 sec)
-
docs/pt/docs/advanced/security/http-basic-auth.md
Então nós podemos utilizar o `secrets.compare_digest()` para garantir que o `credentials.username` é `"stanleyjobson"`, e que o `credentials.password` é `"swordfish"`. //// tab | Python 3.9+ ```Python hl_lines="1 12-24" {!> ../../docs_src/security/tutorial007_an_py39.py!} ``` //// //// tab | Python 3.8+ ```Python hl_lines="1 12-24"
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Sun Oct 06 20:36:54 UTC 2024 - 6.2K bytes - Viewed (0) -
docs/em/docs/advanced/security/http-basic-auth.md
⤴️ 👥 💪 ⚙️ `secrets.compare_digest()` 🚚 👈 `credentials.username` `"stanleyjobson"`, & 👈 `credentials.password` `"swordfish"`. ```Python hl_lines="1 11-21" {!../../docs_src/security/tutorial007.py!} ``` 👉 🔜 🎏: ```Python if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"): # Return some error ... ``` ✋️ ⚙️ `secrets.compare_digest()` ⚫️ 🔜 🔐 🛡 🆎 👊 🤙 "🕰 👊".
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Sun Oct 06 20:36:54 UTC 2024 - 4.1K bytes - Viewed (0) -
docs/zh/docs/advanced/security/http-basic-auth.md
# Return some error ... ``` 但使用 `secrets.compare_digest()`,可以防御**时差攻击**,更加安全。 ### 时差攻击 什么是**时差攻击**? 假设攻击者试图猜出用户名与密码。 他们发送用户名为 `johndoe`,密码为 `love123` 的请求。 然后,Python 代码执行如下操作: ```Python if "johndoe" == "stanleyjobson" and "love123" == "swordfish": ... ```
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Sun Oct 06 20:36:54 UTC 2024 - 5.2K bytes - Viewed (0) -
docs/de/docs/advanced/security/http-basic-auth.md
{* ../../docs_src/security/tutorial007_an_py39.py hl[1,12:24] *} Dies wäre das gleiche wie: ```Python if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"): # Einen Error zurückgeben ... ```
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Sun Oct 27 15:25:54 UTC 2024 - 5.8K bytes - Viewed (0) -
docs/en/docs/advanced/security/http-basic-auth.md
{* ../../docs_src/security/tutorial007_an_py39.py hl[1,12:24] *} This would be similar to: ```Python if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"): # Return some error ... ```
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Sat Oct 26 16:01:27 UTC 2024 - 4.8K bytes - Viewed (0) -
docs_src/security/tutorial007_an.py
is_correct_username = secrets.compare_digest( current_username_bytes, correct_username_bytes ) current_password_bytes = credentials.password.encode("utf8") correct_password_bytes = b"swordfish" is_correct_password = secrets.compare_digest( current_password_bytes, correct_password_bytes ) if not (is_correct_username and is_correct_password): raise HTTPException(
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Tue Mar 26 16:56:53 UTC 2024 - 1.2K bytes - Viewed (0) -
docs_src/security/tutorial007.py
is_correct_username = secrets.compare_digest( current_username_bytes, correct_username_bytes ) current_password_bytes = credentials.password.encode("utf8") correct_password_bytes = b"swordfish" is_correct_password = secrets.compare_digest( current_password_bytes, correct_password_bytes ) if not (is_correct_username and is_correct_password): raise HTTPException(
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Thu Jan 11 14:33:05 UTC 2024 - 1.1K bytes - Viewed (0) -
docs_src/security/tutorial007_an_py39.py
is_correct_username = secrets.compare_digest( current_username_bytes, correct_username_bytes ) current_password_bytes = credentials.password.encode("utf8") correct_password_bytes = b"swordfish" is_correct_password = secrets.compare_digest( current_password_bytes, correct_password_bytes ) if not (is_correct_username and is_correct_password): raise HTTPException(
Registered: Sun Nov 03 07:19:11 UTC 2024 - Last Modified: Tue Mar 26 16:56:53 UTC 2024 - 1.1K bytes - Viewed (0)