*
 * b0b1s7 is the section prefix. If a section is omitted, that means its ranges data exactly matches
 * that of the preceding section.
 *
 * b2b3s2 is the offset into the ranges data. It is shifted by 2 because ranges are 4-byte aligned.
 *
 * Mappings Data (4,719 bytes)
 * ===========================
 *
 * This is UTF-8 character data. It is indexed into by b2b3 in the ranges dataset.
 *
 * Mappings may overlap.
 *
 * ASCII-Only

  return result.toMap()
}

/**
 * Modifies [ranges] to combine any adjacent [MappedRange.InlineDelta] of same size to single entry.
 * @returns same instance of [ranges] for convenience
 */
internal fun mergeAdjacentDeltaMappedRanges(ranges: MutableList<MappedRange>): MutableList<MappedRange> {
  var i = 0
  while (i < ranges.size) {
    val curr = ranges[i]
    if (curr is MappedRange.InlineDelta) {
      val j = i + 1

 * rangeSet.add(Range.closedOpen(15, 20)); // connected range; {[1, 10], [11, 20)}
 * rangeSet.add(Range.openClosed(0, 0)); // empty range; {[1, 10], [11, 20)}
 * rangeSet.remove(Range.open(5, 10)); // splits [1, 10]; {[1, 5], [10, 10], [11, 20)}
 * }
 *
 * <p>Note that the behavior of {@link Range#isEmpty()} and {@link Range#isConnected(Range)} may not

     * but overlapping ranges will cause an exception when {@link #build()} is called.
     *
     * @throws IllegalArgumentException if {@code range} is empty
     */
    @CanIgnoreReturnValue
    public Builder<C> add(Range<C> range) {
      checkArgument(!range.isEmpty(), "range must not be empty, but was %s", range);
      ranges.add(range);

          RangeMap<Integer, Integer> rangemap =
              ImmutableRangeMap.<Integer, Integer>builder().put(range1, 1).put(range2, 2).build();
          assertEquals(range1.span(range2), rangemap.span());
        }
      }
    }
  }

  public void testGetEntry() {
    for (Range<Integer> range1 : RANGES) {
      for (Range<Integer> range2 : RANGES) {

   * also be called their <i>union</i>. If they are not, note that the span might contain values
   * that are not contained in either input range.
   *
   * <p>Like {@link #intersection(Range) intersection}, this operation is commutative, associative
   * and idempotent. Unlike it, it is always well-defined for any two input ranges.
   */
  public Range<C> span(Range<C> other) {

 * rangeSet.add(Range.closedOpen(15, 20)); // connected range; {[1, 10], [11, 20)}
 * rangeSet.add(Range.openClosed(0, 0)); // empty range; {[1, 10], [11, 20)}
 * rangeSet.remove(Range.open(5, 10)); // splits [1, 10]; {[1, 5], [10, 10], [11, 20)}
 * }
 *
 * <p>Note that the behavior of {@link Range#isEmpty()} and {@link Range#isConnected(Range)} may not

.daterangepicker .ranges {
  float: none;
  text-align: left;
  margin: 0;
}

.daterangepicker.show-calendar .ranges {
  margin-top: 8px;
}

.daterangepicker .ranges ul {
  list-style: none;
  margin: 0 auto;
  padding: 0;
  width: 100%;
}

.daterangepicker .ranges li {
  font-size: 12px;
  padding: 8px 12px;
  cursor: pointer;
}

.daterangepicker .ranges li:hover {

          RangeMap<Integer, Integer> rangemap =
              ImmutableRangeMap.<Integer, Integer>builder().put(range1, 1).put(range2, 2).build();
          assertEquals(range1.span(range2), rangemap.span());
        }
      }
    }
  }

  public void testGetEntry() {
    for (Range<Integer> range1 : RANGES) {
      for (Range<Integer> range2 : RANGES) {

  public void addAll(Iterable<Range<C>> ranges) {
    for (Range<C> range : ranges) {
      add(range);
    }
  }

  @Override
  public void removeAll(RangeSet<C> other) {
    removeAll(other.asRanges());
  }

  @Override
  public void removeAll(Iterable<Range<C>> ranges) {
    for (Range<C> range : ranges) {
      remove(range);
    }
  }

  @Override
  public boolean intersects(Range<C> otherRange) {