"five", 5,
            "six", 6,
            "seven", 7,
            "eight", 8),
        "one",
        1,
        "two",
        2,
        "three",
        3,
        "four",
        4,
        "five",
        5,
        "six",
        6,
        "seven",
        7,
        "eight",
        8);
    assertMapEquals(
        ImmutableBiMap.of(
            "one", 1,

  internal const val B1_FLAG_MASK = 128

  /**
   * Byte 1 mask for the payload length.
   *
   * If this value is [PAYLOAD_SHORT], the next two
   * bytes represent the length. If this value is [PAYLOAD_LONG], the next eight bytes
   * represent the length.
   */
  internal const val B1_MASK_LENGTH = 127

  internal const val OPCODE_CONTINUATION = 0x0
  internal const val OPCODE_TEXT = 0x1
  internal const val OPCODE_BINARY = 0x2

            "five", 5,
            "six", 6,
            "seven", 7,
            "eight", 8),
        "one",
        1,
        "two",
        2,
        "three",
        3,
        "four",
        4,
        "five",
        5,
        "six",
        6,
        "seven",
        7,
        "eight",
        8);
    assertMapEquals(
        ImmutableMap.of(
            "one", 1,

redundancy or better drive space utilization.

To get an idea of how various combinations of data and parity drives affect the storage usage, let’s take an example of a 100 MiB file stored
on 16 drive MinIO deployment. If you use eight data and eight parity drives, the file space usage will be approximately twice, i.e. 100 MiB
file will take 200 MiB space. But, if you use ten data and six parity drives, same 100 MiB file takes around 160 MiB. If you use 14 data and

            "five", 5,
            "six", 6,
            "seven", 7,
            "eight", 8),
        "one",
        1,
        "two",
        2,
        "three",
        3,
        "four",
        4,
        "five",
        5,
        "six",
        6,
        "seven",
        7,
        "eight",
        8);
    assertMapEquals(
        ImmutableMap.of(
            "one", 1,

    return Ints.fromBytes(b4, b3, b2, b1);
  }

  /**
   * Reads a {@code long} as specified by {@link DataInputStream#readLong()}, except using
   * little-endian byte order.
   *
   * @return the next eight bytes of the input stream, interpreted as a {@code long} in
   *     little-endian byte order
   * @throws IOException if an I/O error occurs
   */
  @CanIgnoreReturnValue // to skip some bytes
  @Override

 * or implied. See the License for the specific language governing permissions and limitations under
 * the License.
 */

/**
 * Static utilities for the eight primitive types and {@code void}, and value types for treating
 * them as unsigned or storing them in immutable arrays.
 *
 * <p>This package is a part of the open-source <a href="https://github.com/google/guava">Guava</a>

        leftt ^= work;
        right ^= (work << 2);

        work   = ((right >>>  8) ^ leftt) & 0x00ff00ff;
        leftt ^= work;
        right ^= (work << 8);
        right  = (right << 1) | ((right >>> 31) & 1);

        work   = (leftt ^ right) & 0xaaaaaaaa;
        leftt ^= work;
        right ^= work;
        leftt  = (leftt << 1) | ((leftt >>> 31) & 1);

   * {@link StandardCharsets#ISO_8859_1} instead.
   *
   */
  public static final Charset ISO_8859_1 = StandardCharsets.ISO_8859_1;

  /**
   * UTF-8: eight-bit UCS Transformation Format.
   *
   * <p><b>Note:</b> this constant is now unnecessary and should be treated as deprecated; use
   * {@link StandardCharsets#UTF_8} instead.
   *
   */

                (byte) 0x05, (byte) 0x06, (byte) 0x07, (byte) 0x08
              },
              0x89abcdef,
              0x0123456789abcdefL, // asInt/asLong as above, due to equal eight first bytes
              "efcdab89674523010102030405060708"),
          new ExpectedHashCode(
              new byte[] {(byte) 0xdf, (byte) 0x9b, (byte) 0x57, (byte) 0x13},
              0x13579bdf,
              null,