<modelVersion>4.0.0</modelVersion>

    <groupId>org.apache.maven.its</groupId>
    <artifactId>parent</artifactId>
    <version>0.1</version>
    <packaging>pom</packaging>

    <name>Maven Integration Test :: Dummy Parent</name>

    <build>
        <pluginManagement>
            <plugins>
                <plugin>

    ```Python hl_lines="3  10-14"
    {!> ../../../docs_src/security/tutorial002_py310.py!}
    ```

## `get_current_user` 의존성 생성하기

의존성 `get_current_user`를 만들어 봅시다.

의존성이 하위 의존성을 가질 수 있다는 것을 기억하십니까?

`get_current_user`는 이전에 생성한 것과 동일한 `oauth2_scheme`과 종속성을 갖게 됩니다.

이전에 *경로 작동*에서 직접 수행했던 것과 동일하게 새 종속성 `get_current_user`는 하위 종속성 `oauth2_scheme`에서 `str`로 `token`을 수신합니다.

=== "파이썬 3.7 이상"

    ```Python hl_lines="25"

    ```Python hl_lines="5  12-16"
    {!> ../../../docs_src/security/tutorial002.py!}
    ```

## Eine `get_current_user`-Abhängigkeit erstellen

Erstellen wir eine Abhängigkeit `get_current_user`.

Erinnern Sie sich, dass Abhängigkeiten Unterabhängigkeiten haben können?

`get_current_user` wird seinerseits von `oauth2_scheme` abhängen, das wir zuvor erstellt haben.

{!../../../docs_src/security/tutorial002.py!}
```

## 创建 `get_current_user` 依赖项

创建 `get_current_user` 依赖项。

还记得依赖项支持子依赖项吗？

`get_current_user` 使用 `oauth2_scheme` 作为依赖项。

与之前直接在路径操作中的做法相同，新的 `get_current_user` 依赖项从子依赖项 `oauth2_scheme` 中接收 `str` 类型的 `token`：

```Python hl_lines="25"
{!../../../docs_src/security/tutorial002.py!}
```

## 获取用户

`get_current_user` 使用创建的（伪）工具函数，该函数接收 `str` 类型的令牌，并返回 Pydantic 的 `User` 模型：

Harshavardhana <******@****.***> 1714766900 -0700

setattr(_current_module, "keras", _KerasLazyLoader(globals()))
_module_dir = _module_util.get_parent_dir_for_name("keras._tf_keras.keras")
_current_module.__path__ = [_module_dir] + _current_module.__path__
if _tf_uses_legacy_keras:
  _module_dir = _module_util.get_parent_dir_for_name("tf_keras.api._v2.keras")
else:
  _module_dir = _module_util.get_parent_dir_for_name("keras.api._v2.keras")

    val parent = nonContainerParent
    return when {
        parent is R && check(parent, this) -> parent
        parent is KtQualifiedExpression && parent.selectorExpression == this -> {
            val grandParent = parent.nonContainerParent
            when {
                grandParent is R && check(grandParent, parent) -> grandParent
                else -> null
            }

        .inOrder();
  }

  @AndroidIncompatible // Android forbids null parent ClassLoader
  public void testClassPathEntries_duplicateUri_parentWins() throws Exception {
    URL url = new URL("file:/a");
    URLClassLoader parent = new URLClassLoader(new URL[] {url}, null);
    URLClassLoader child = new URLClassLoader(new URL[] {url}, parent) {};

        var parent = parent
        while (parent is KtDotQualifiedExpression) {
            if (parent.selectorExpression !== this) return true
            parent = parent.parent
        }
        return false
    }

    private fun KtSimpleNameExpression.isPartOfUserTypeRefQualifier(): Boolean {
        var parent = parent
        while (parent is KtUserType) {

 defined the maven.multiproject.includes property in any of his properties
 files for the current project. if yes. then I'm able to find projects that
 can be offered to be opened together with the current project.
 problems with the current solution are:
 1. information is duplicate. once in POM's dependencies and once in the
 maven.multiproject.includes property.