add(elements.next());
      }
      return this;
    }

    private void dedupAndCoalesceAndDeleteEmpty() {
      dedupAndCoalesce(false);

      // If there was a setCount(elem, 0), those elements are still present.  Eliminate them.
      int size = 0;
      for (int i = 0; i < length; i++) {
        if (counts[i] > 0) {
          elements[size] = elements[i];
          counts[size] = counts[i];

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an entry for each type parameter.
</p>

<p>
For example, given the type equation with the bound type parameter
<code>P</code>
</p>

<pre>
	[10]struct{ elem P, list []P } ≡<sub>A</sub> [10]struct{ elem string; list []string }
</pre>

<p>
type inference starts with an empty map.
Unification first compares the top-level structure of the LHS and RHS
types.

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