return standardToArray(array);
    }

    @Override
    public String toString() {
      return standardToString();
    }

    @Override
    public boolean equals(@Nullable Object object) {
      return standardEquals(object);
    }

    @Override
    public int hashCode() {
      return standardHashCode();
    }

    @Override

      assertBitEquals(x.get(i), y.get(i));
    }

    AtomicDoubleArray a = new AtomicDoubleArray(VALUES);
    AtomicDoubleArray b = serialClone(a);
    assertFalse(a.equals(b));
    assertFalse(b.equals(a));
    assertEquals(a.length(), b.length());
    for (int i = 0; i < VALUES.length; i++) {
      assertBitEquals(a.get(i), b.get(i));
    }
  }

  /** toString returns current value */

    @SuppressWarnings("EqualsHashCode")
    @Override
    public boolean equals(@Nullable Object other) {
      return (other instanceof ClassWhichIsAlwaysEqualButHasDifferentHashcodes);
    }
  }

  private static class ObjectWhichIsEqualButChangesClass implements Serializable {
    private static final long serialVersionUID = 1L;

    @Override
    public boolean equals(@Nullable Object other) {

      return parent.subArray(fromIndex, toIndex).asList();
    }

    @Override
    public boolean equals(@CheckForNull Object object) {
      if (object instanceof AsList) {
        AsList that = (AsList) object;
        return this.parent.equals(that.parent);
      }
      // We could delegate to super now but it would still box too much
      if (!(object instanceof List)) {

  public <T extends @Nullable Object> T[] toArray(T[] other) {
    return delegate.toArray(other);
  }

  @Override
  public String toString() {
    return delegate.toString();
  }

  // TODO(cpovirk): equals(), as well, in case it's any faster than Sets.equalsImpl?

  @Override
  public int hashCode() {
    return delegate.hashCode();
  }

        equivalence =
            Equivalence.equals()
                .onResultOf(ImmutableSortedMap<String, Integer>::comparator)
                .and(Equivalence.equals().onResultOf(map -> map.entrySet().asList()))
                .and(Equivalence.equals());
    ImmutableSortedMap<String, Integer> expected =

   * Chooses and returns the representative instance for any of a collection of instances that are
   * equal to each other. If two {@linkplain Object#equals equal} inputs are given to this method,
   * both calls will return the same instance. That is, {@code intern(a).equals(a)} always holds,
   * and {@code intern(a) == intern(b)} if and only if {@code a.equals(b)}. Note that {@code

    this.element = Preconditions.checkNotNull(element);
  }

  @Override
  public int size() {
    return 1;
  }

  @Override
  public boolean contains(@CheckForNull Object target) {
    return element.equals(target);
  }

  @Override
  public UnmodifiableIterator<E> iterator() {
    return Iterators.singletonIterator(element);
  }

  @Override
  public ImmutableList<E> asList() {

   * their map views, as returned by {@link #asMap}, are also equal.
   *
   * <p>In general, two multimaps with identical key-value mappings may or may not be equal,
   * depending on the implementation. For example, two {@link SetMultimap} instances with the same
   * key-value mappings are equal, but equality of two {@link ListMultimap} instances depends on the

        .addEqualityGroup(Predicates.equalTo(1), Predicates.equalTo(1))
        .addEqualityGroup(Predicates.equalTo(2))
        .addEqualityGroup(Predicates.<@Nullable Integer>equalTo(null))
        .testEquals();
  }

  @J2ktIncompatible
  @GwtIncompatible // SerializableTester
  public void testIsEqualTo_serialization() {
    checkSerialization(Predicates.equalTo(1));
  }