* invoke interruptTask on any subsequent futures.
         */
        callInterruptTask = false;
      }
      // We call this before the listeners in order to avoid needing to manage a separate stack data
      // structure for them.  Also, some implementations rely on this running prior to listeners
      // so that the cleanup work is visible to listeners.

    assertSame(valueThree, newFirst.getValueReference().get());
    assertEquals(hashThree, newFirst.getHash());
    assertSame(entryOne, newFirst.getNext());

    // tail (remaining entries are copied in reverse order)
    newFirst = segment.removeEntryFromChain(entryThree, entryOne);
    assertSame(keyTwo, newFirst.getKey());
    assertSame(valueTwo, newFirst.getValueReference().get());
    assertEquals(hashTwo, newFirst.getHash());

    assertSame(valueThree, newFirst.getValueReference().get());
    assertEquals(hashThree, newFirst.getHash());
    assertSame(entryOne, newFirst.getNext());

    // tail (remaining entries are copied in reverse order)
    newFirst = segment.removeEntryFromChain(entryThree, entryOne);
    assertSame(keyTwo, newFirst.getKey());
    assertSame(valueTwo, newFirst.getValueReference().get());
    assertEquals(hashTwo, newFirst.getHash());

   * they were inserted into the builder. For example, in the above example, {@code
   * WORD_TO_INT.entrySet()} is guaranteed to iterate over the entries in the order {@code "one"=1,
   * "two"=2, "three"=3}, and {@code keySet()} and {@code values()} respect the same order. If you
   * want a different order, consider using {@link #orderEntriesByValue(Comparator)}, which changes

        .withFeatures(
            SetFeature.GENERAL_PURPOSE,
            CollectionFeature.SERIALIZABLE,
            CollectionFeature.ALLOWS_NULL_VALUES,
            CollectionFeature.KNOWN_ORDER,
            CollectionFeature.FAILS_FAST_ON_CONCURRENT_MODIFICATION,
            CollectionSize.ANY)
        .suppressing(suppressForLinkedHashSet())
        .createTestSuite();
  }

            MapFeature.ALLOWS_NULL_VALUES,
            MapFeature.FAILS_FAST_ON_CONCURRENT_MODIFICATION,
            MapFeature.RESTRICTS_KEYS,
            MapFeature.RESTRICTS_VALUES,
            CollectionFeature.KNOWN_ORDER,
            CollectionFeature.SUPPORTS_ITERATOR_REMOVE,
            CollectionFeature.SERIALIZABLE,
            CollectionSize.ANY)
        .suppressing(suppressForCheckedNavigableMap())
        .createTestSuite();

                    }
                    return multimap;
                  }

                  @Override
                  public Iterable<Entry<String, String>> order(
                      List<Entry<String, String>> insertionOrder) {
                    return new Ordering<Entry<String, String>>() {
                      @Override

  }

  /**
   * Returns an immutable set instance containing the given enum elements. Internally, the returned
   * set will be backed by an {@link EnumSet}.
   *
   * <p>The iteration order of the returned set follows the enum's iteration order, not the order in
   * which the elements are provided to the method.
   *
   * @param anElement one of the elements the set should contain

   * Generation, described in Knuth's "The Art of Computer Programming", Volume 4, Chapter 7,
   * Section 7.2.1.2. The iteration order follows the lexicographical order. This means that the
   * first permutation will be in ascending order, and the last will be in descending order.
   *
   * <p>Duplicate elements are considered equal. For example, the list [1, 1] will have only one

            return ((Integer) object) % 5; // fake tons of collisions!
          }
        };

    // Don't let the elements be in such a predictable order
    list = shuffledCopy(list, new Random(1));

    Collections.sort(list, arbitrary);

    // Now we don't care what order it's put the list in, only that
    // comparing any pair of elements gives the answer we expect.
    Helpers.testComparator(arbitrary, list);
  }