/*
       * The returned string will be from the end of the last match to the beginning of the next
       * one. nextStart is the start position of the returned substring, while offset is the place
       * to start looking for a separator.
       */
      int nextStart = offset;
      while (offset != -1) {
        int start = nextStart;
        int end;

        int separatorPosition = separatorStart(offset);

        entryOf(k4, v4),
        entryOf(k5, v5),
        entryOf(k6, v6),
        entryOf(k7, v7),
        entryOf(k8, v8),
        entryOf(k9, v9),
        entryOf(k10, v10));
  }

  // looking for of() with > 10 entries? Use the builder or ofEntries instead.

  /**
   * Returns an immutable map containing the given entries, in order.
   *

automatically on GitHub.

If you want to contribute, start working through the TensorFlow codebase,
navigate to the
[GitHub "issues" tab](https://github.com/tensorflow/tensorflow/issues) and start
looking through interesting issues. If you are not sure of where to start, then
start by trying one of the smaller/easier issues here i.e.

    builder.put(k1, v1);
    builder.put(k2, v2);
    builder.put(k3, v3);
    builder.put(k4, v4);
    builder.put(k5, v5);
    return builder.build();
  }

  // looking for of() with > 5 entries? Use the builder instead.

  /** Returns a new {@link Builder}. */
  public static <K, V> Builder<K, V> builder() {
    return new Builder<>();
  }

  /**

   */
  public static <K, V> ImmutableMultimap<K, V> of(
      K k1, V v1, K k2, V v2, K k3, V v3, K k4, V v4, K k5, V v5) {
    return ImmutableListMultimap.of(k1, v1, k2, v2, k3, v3, k4, v4, k5, v5);
  }

  // looking for of() with > 5 entries? Use the builder instead.

  /**
   * Returns a new builder. The generated builder is equivalent to the builder created by the {@link
   * Builder} constructor.
   */

    return new RegularImmutableBiMap<K, V>(
        new Object[] {
          k1, v1, k2, v2, k3, v3, k4, v4, k5, v5, k6, v6, k7, v7, k8, v8, k9, v9, k10, v10
        },
        10);
  }

  // looking for of() with > 10 entries? Use the builder or ofEntries instead.

  /**
   * Returns an immutable map containing the given entries, in order.
   *

   */
  public static <K, V> ImmutableMultimap<K, V> of(
      K k1, V v1, K k2, V v2, K k3, V v3, K k4, V v4, K k5, V v5) {
    return ImmutableListMultimap.of(k1, v1, k2, v2, k3, v3, k4, v4, k5, v5);
  }

  // looking for of() with > 5 entries? Use the builder instead.

  /**
   * Returns a new builder. The generated builder is equivalent to the builder created by the {@link
   * Builder} constructor.
   */

      /*
       * The returned string will be from the end of the last match to the beginning of the next
       * one. nextStart is the start position of the returned substring, while offset is the place
       * to start looking for a separator.
       */
      int nextStart = offset;
      while (offset != -1) {
        int start = nextStart;
        int end;

        int separatorPosition = separatorStart(offset);

    builder.put(k1, v1);
    builder.put(k2, v2);
    builder.put(k3, v3);
    builder.put(k4, v4);
    builder.put(k5, v5);
    return builder.build();
  }

  // looking for of() with > 5 entries? Use the builder instead.

  /** Returns a new {@link Builder}. */
  public static <K, V> Builder<K, V> builder() {
    return new Builder<>();
  }

  /**

---

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