}
	// for every resource in flight
	for _, ipr := range r.inProgressResources {
		res := ipr.Resource
		key := res.String()
		// for every version (nonce) of the config currently in play
		for nonce, dataplanes := range r.reverseStatus {

			// check to see if this version of the config contains this version of the resource

    }

    @Nullable
    ExcludeSpec tryIntersect(ExcludeSpec left, ExcludeSpec right) {
        if (left.equals(right)) {
            return left;
        } else {
            return intersections.stream()
                .filter(i -> i.applies(left, right))
                .findFirst()
                .map(i -> i.intersect(left, right, factory))
                .orElse(null);
        }
    }

    @NonNullApi

                          </td>
            <td>
              Thu Sep 29 21:19:50 CEST 2011
            </td>
            <td align="right">
                              817
                          </td>
            <td>
              &nbsp;
            </td>
          </tr>
                  <tr>
            <td>

<code>R0&lt;&lt;16</code>
<br>
<code>R0@&gt;16</code>:
For <code>&lt;&lt;</code>, left shift <code>R0</code> by 16 bits.
The other codes are <code>-&gt;</code> (arithmetic right shift),
<code>&gt;&gt;</code> (logical right shift), and
<code>@&gt;</code> (rotate right).
</li>

<li>
<code>R0-&gt;R1</code>
<br>
<code>R0&gt;&gt;R1</code>
<br>
<code>R0&lt;&lt;R1</code>
<br>
<code>R0@&gt;R1</code>:

---

If you just don't know, use normal `def`.

---

**Note**: You can mix `def` and `async def` in your *path operation functions* as much as you need and define each one using the best option for you. FastAPI will do the right thing with them.

Anyway, in any of the cases above, FastAPI will still work asynchronously and be extremely fast.

But by following the steps above, it will be able to do some performance optimizations.

        task.nested = new Tree(value: "root", right: new Tree(value: "right", right: new Tree(value: "right")))

        when:
        visitProperties(task)

        then:
        _ * visitor.visitNested() >> true
        noExceptionThrown()
        task.nested.right == task.nested.right.right
    }

    def "nested beans can be re-used"() {

      successor(pred(), succ());
      if (left == null) {
        return right;
      } else if (right == null) {
        return left;
      } else if (left.height >= right.height) {
        AvlNode<E> newTop = pred();
        // newTop is the maximum node in my left subtree
        newTop.left = left.removeMax(newTop);
        newTop.right = right;
        newTop.distinctElements = distinctElements - 1;

     *
     * ```kt
     * fun usage(action: String.(Int) -> String) {
     *   "hello".<expr>action</expr>(10)
     * }
     * ```
     *
     * The user might want to know the type of the `action` callback. If we always return null for the named references,
     * we won't be able to handle this request, and just return null. So the user will only be able to see the type

      successor(pred(), succ());
      if (left == null) {
        return right;
      } else if (right == null) {
        return left;
      } else if (left.height >= right.height) {
        AvlNode<E> newTop = pred();
        // newTop is the maximum node in my left subtree
        newTop.left = left.removeMax(newTop);
        newTop.right = right;
        newTop.distinctElements = distinctElements - 1;

     */
    long deadline = System.nanoTime() + unit.toNanos(timeout);
    int added = 0;
    while (added < numElements) {
      // we could rely solely on #poll, but #drainTo might be more efficient when there are multiple
      // elements already available (e.g. LinkedBlockingQueue#drainTo locks only once)
      added += q.drainTo(buffer, numElements - added);