//// tab | Тест

`pip install "foo[bar]"`

Примеры строковых литералов во фрагментах кода: `"this"`, `'that'`.

Сложный пример строковых литералов во фрагментах кода: `f"I like {'oranges' if orange else "apples"}"`

Хардкор: `Yesterday, my friend wrote: "If you spell incorrectly correctly, you have spelled it incorrectly". To which I answered: "Correct, but 'incorrectly' is incorrectly not '"incorrectly"'"`

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//// tab | Test

`pip install "foo[bar]"`

Beispiele für Stringliterale in Codeschnipseln: `"this"`, `'that'`.

Ein schwieriges Beispiel für Stringliterale in Codeschnipseln: `f"I like {'oranges' if orange else "apples"}"`

Hardcore: `Yesterday, my friend wrote: "If you spell incorrectly correctly, you have spelled it incorrectly". To which I answered: "Correct, but 'incorrectly' is incorrectly not '"incorrectly"'"`

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//// tab | Test

`pip install "foo[bar]"`

Examples for string literals in code snippets: `"this"`, `'that'`.

A difficult example for string literals in code snippets: `f"I like {'oranges' if orange else "apples"}"`

Hardcore: `Yesterday, my friend wrote: "If you spell incorrectly correctly, you have spelled it incorrectly". To which I answered: "Correct, but 'incorrectly' is incorrectly not '"incorrectly"'"`

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//// tab | Prueba

`pip install "foo[bar]"`

Ejemplos de literales de string en fragmentos de código: `"this"`, `'that'`.

Un ejemplo difícil de literales de string en fragmentos de código: `f"I like {'oranges' if orange else "apples"}"`

Hardcore: `Yesterday, my friend wrote: "If you spell incorrectly correctly, you have spelled it incorrectly". To which I answered: "Correct, but 'incorrectly' is incorrectly not '"incorrectly"'"`

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//// tab | Teste

`pip install "foo[bar]"`

Exemplos de literais de string em trechos de código: `"this"`, `'that'`.

Um exemplo difícil de literais de string em trechos de código: `f"I like {'oranges' if orange else "apples"}"`

Pesado: `Yesterday, my friend wrote: "If you spell incorrectly correctly, you have spelled it incorrectly". To which I answered: "Correct, but 'incorrectly' is incorrectly not '"incorrectly"'"`

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    assertSame(comparator, comparator.reverse());

    assertEquals(0, comparator.compare(null, null));
    assertEquals(0, comparator.compare(new Object(), new Object()));
    assertEquals(0, comparator.compare("apples", "oranges"));
    assertSame(comparator, reserialize(comparator));
    assertEquals("Ordering.allEqual()", comparator.toString());

    List<String> strings = ImmutableList.of("b", "a", "d", "c");

    assertSame(comparator, comparator.reverse());

    assertEquals(0, comparator.compare(null, null));
    assertEquals(0, comparator.compare(new Object(), new Object()));
    assertEquals(0, comparator.compare("apples", "oranges"));
    assertSame(comparator, reserialize(comparator));
    assertEquals("Ordering.allEqual()", comparator.toString());

    List<String> strings = ImmutableList.of("b", "a", "d", "c");

   * also be called their <i>union</i>. If they are not, note that the span might contain values
   * that are not contained in either input range.
   *
   * <p>Like {@link #intersection(Range) intersection}, this operation is commutative, associative
   * and idempotent. Unlike it, it is always well-defined for any two input ranges.
   */
  public Range<C> span(Range<C> other) {

      for (Range<Integer> range2 : ranges) {
        if (!range1.isConnected(range2) || range1.intersection(range2).isEmpty()) {
          ImmutableRangeSet<Integer> rangeSet =
              ImmutableRangeSet.<Integer>builder().add(range1).add(range2).build();
          for (Range<Integer> subRange : subRanges) {
            RangeSet<Integer> expected = TreeRangeSet.create();
            for (Range<Integer> range : rangeSet.asRanges()) {

          RangeMap<Integer, Integer> rangemap =
              ImmutableRangeMap.<Integer, Integer>builder().put(range1, 1).put(range2, 2).build();
          assertEquals(range1.span(range2), rangemap.span());
        }
      }
    }
  }

  public void testGetEntry() {
    for (Range<Integer> range1 : RANGES) {
      for (Range<Integer> range2 : RANGES) {